Question

The perimeter of an isosceles triangle is 32 inches. If the base is longer than half of the two other equal sides by 2 inches, find the length of all sides of this triangle.
Write as a equation.​

Answer 1

Answer:

Step-by-step explanation:

Let equal sides of an isosceles triangle = a inches

Base = $\frac{1}{2}a+2$ inches

Perimeter  = 32 inches

a + a + $\frac{1}{2}a+2$ = 32

$2a + \frac{1}{2}a+2 = 32\\\\\frac{2a*2}{1*2}+\frac{1}{2}a+2=32\\\\\frac{4a}{2}+\frac{1}{2}a+2=32\\\\\frac{5}{2}a+2 = 32$

Subtract 2 from both sides

$\frac{5}{2}a=32-2\\\\\frac{5}{2}a=30\\\\a=30*\frac{2}{5}\\\\a=6*2$

a = 12 inches

base = $\frac{1}{2}*12+2$

        = 6 + 2

Base = 8 inches