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3 years ago

A square has the following vertices. Find the area of the square.

Mathematics

1 answer:

Wewaii [24]3 years ago

6 0

Answer:

18 square units

Step-by-step explanation:

Since the shape is a square lets find the distance between two close point then square the distance to find the answer.

Lets take the point (-7,-5), (-4,-2)

Distance= √((y2-y1)²+(x2-x1)²)

Distance= √((-2--5)²+(-4--7)²)

Distance= √((-2+5)²+(-4+7)²)

Distance= √((3)²+(3)²)

Distance= √(9+9)

Distance= √18 units

Area= distance ²

area= √18²

Area= 18 square unit

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gtnhenbr [62]

Answer:

Step-by-step explanation:

Given is a differential equation as

$ty' + 6y = t^2 - t + 1, y(1) = 1 6 , t > 0$

Divide this by t to get in linear form

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This is of the form

y' +p(t) y = Q(t)

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So solution would be

$yt = \int t^2-t+1 dt\\= t^3/3-t^2/2+t+C$

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3 years ago

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algol [13]

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Hope this helps!

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3 years ago

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ollegr [7]

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Step-by-step explanation:

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