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Brrunno [24]
2 years ago
8

A square has the following vertices. Find the area of the square.

Mathematics
1 answer:
Wewaii [24]2 years ago
6 0

Answer:

18 square units

Step-by-step explanation:

Since the shape is a square lets find the distance between two close point then square the distance to find the answer.

Lets take the point (-7,-5), (-4,-2)

Distance= √((y2-y1)²+(x2-x1)²)

Distance= √((-2--5)²+(-4--7)²)

Distance= √((-2+5)²+(-4+7)²)

Distance= √((3)²+(3)²)

Distance= √(9+9)

Distance= √18 units

Area= distance ²

area= √18²

Area= 18 square unit

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kobusy [5.1K]

Answer:

  -9

Step-by-step explanation:

  \sqrt{\dfrac{50}{2}}\cdot(-4)+\sqrt{121}=-4\sqrt{25}+11=-4\cdot5+11\\\\=-20+11=\boxed{-9}

Your calculator can help with this.

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2 years ago
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3 years ago
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3 years ago
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aliina [53]
AB = 6 cm, AC = 12 cm, CD = ?

In triangle ABC, ∠CBA = 90°, therefore in triangle BCD ∠CBD = 90° also.

Since ∠BDC = 55°, ∠CBD = 90°, and there are 180 degrees in a triangle, we know ∠DCB = 180 - 55 - 90 = 35°

In order to find ∠BCA, use the law of sines:
 
sin(∠BCA)/BA = sin(∠CBA)/CA
sin(∠BCA)/6 cm = sin(90)/12 cm
sin(∠BCA) = 6*(1)/12 = 0.5
∠BCA = arcsin(0.5) = 30° or 150°
We know the sum of all angles in a triangle must be 180°, so we choose the value 30° for ∠BCA

Now add ∠BCA (30°) to ∠DCB = 35° to find ∠DCA.
∠DCA = 30 + 35 = 65°

Since triangle DCA has 180°, we know ∠CAD = 180 - ∠DCA - ∠ADC = 180 - 65 - 55 = 60°

In triangle DCA we now have all three angles and one side, so we can use the law of sines to find the length of DC.

12cm/sin(∠ADC) = DC/sin(∠DCA)
12cm/sin(55°) = DC/sin(60°)
DC = 12cm*sin(60°)/sin(55°)
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3 years ago
Express each rational number as a fraction or mixed number in simplest form. <img src="https://tex.z-dn.net/?f=%5Csqrt%7B25%7D"
siniylev [52]

Answer:

\sqrt{25} In its simplist form is 5.

Step-by-step explanation:

6 0
3 years ago
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