Triangle ABD is i<span>nscribed in circle and </span>has hypotenuse as circle's diameter so angle ABD must be 90°
Since it is parallelogram, ∠ABD = ∠BDC = 90° and it is given that ∠ADB = 30°
So we have ∠CDO = ∠CDB + ∠ADB = 30° + 90° = 120°
Final answers: ∠CDO = 120° and ∠ABD = 90°
Y = -5
work:
y = |5| - 10
y = 5 - 10
y = -5
Answer:
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The LCD of 2 and 41 is 82 so we write 1/2 as 41/82:-
7 41/82 - 3 8/82
= 4 33/82 Answer
The answer you are looking for is 5/6
