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marin [14]
2 years ago
8

Look at this plz

Mathematics
1 answer:
Ivan2 years ago
5 0

Answer:

gosh...…. dang brainly why do you have to be like that. you were literally trying to help ppl hippo and they just shut you down like that... ugh why rude.

Step-by-step explanation:

im sorry :(

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What is the slope of <br> y=-x+15
Viefleur [7K]

Answer:

35y

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I need help pls pls I will really appreciate it also l need it step by step pls l will mark you the brainly! pls help!
PIT_PIT [208]

Answer:

1. 8.5

2. 6.7

3. 58.8

4. 415.7

5.6.4

6. 2.5

Step-by-step explanation:

I just used a calc

4 0
3 years ago
An investment account was opened with an initial deposit of 9,600 and earns 7.4% interest compounded continuously, how much will
emmainna [20.7K]

Answer:

10,656

Step-by-step explanation:

I=PRT

I=(9600)(0.074)(15)

Multiply those

I=10,656

3 0
2 years ago
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

6 0
3 years ago
If 3x is one factor of 3x^2-9x, what is the other factor?
Rudik [331]
The answer is:  " (x² − 3) " .
_________________________________
Explanation:
_________________________________

Given:  3x² <span>− 9x ;  factor out a "3x" ; 
_________________________________
 
   </span>→  3x (x² − 3) ;
_________________________________
     The answer is:  " (x² − 3) " .
_________________________________
7 0
3 years ago
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