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marin [14]
3 years ago
8

Look at this plz

Mathematics
1 answer:
Ivan3 years ago
5 0

Answer:

gosh...…. dang brainly why do you have to be like that. you were literally trying to help ppl hippo and they just shut you down like that... ugh why rude.

Step-by-step explanation:

im sorry :(

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What is the quotient when x^3 -5x^2 + 3x -8 is divided by x-3 ?
svetlana [45]

For this case, when making the division of polynomials, we must build a quotient that when multiplied by the divisor of the same as the terms of the dividend, the sign is changed and they are eliminated until reaching the remainder of the division.

It must be fulfilled that:

Dividend = Quotient * Divider + Remainder

When observing the attached figure, the quotient is:

x ^ 2-2x-3

Answer:

x ^ 2-2x-3

See attached image

3 0
3 years ago
Whats the slope ? Please answer
zysi [14]

Answer:

slope = 1

Step-by-step explanation:

slope = rise over run

1 rise for every run

y = x +1

5 0
3 years ago
HELP WITH MATH (PLEASE)
natta225 [31]

Answer:

a to the power of 5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
For which values of a the system has no solution: x≤5, x≥a
soldi70 [24.7K]

Given:

The system of inequalities is

x\leq 5

x\geq a

To find:

The values of a for which the system has no solution.

Solution:

We have,

x\leq 5        ...(1)

It means the value of x is less than or equal to 5.

x\geq a        ...(2)

It means the value of x is greater than or equal to a

Using (1) and (2), we get

a\leq x\leq 5

But if a is great than 5, then there is no value of which satisfies this inequality.

Therefore, the system has no solution for a>5.

7 0
4 years ago
What is the product of 4 left-bracket cosine (StartFraction 2 pi Over 3 EndFraction) + I sine (StartFraction 2 pi Over 3 EndFrac
dlinn [17]

The required product of the function is 8cos\frac{2\pi}{3}cos\frac{\pi}{3}+ 4i cos\frac{2\pi}{3}sin\frac{\pi}{3} + 2i sin\frac{2\pi}{3}cos\frac{\pi}{3} - 4i sin\frac{2\pi}{3}sin\frac{\pi}{3}

We are to find the product of the expression

a =4cos(\frac{2\pi}{3} )+isin(\frac{2\pi}{3})\\b=2cos(\frac{\pi}{3} )+isin(\frac{\pi}{3})\\

The product of the functions is expressed as;

ab = 4cos(\frac{2\pi}{3} )+isin(\frac{2\pi}{3})[2cos(\frac{\pi}{3} )+isin(\frac{\pi}{3}]\\ab=8cos\frac{2\pi}{3}cos\frac{\pi}{3}+ 4i cos\frac{2\pi}{3}sin\frac{\pi}{3} + 2i sin\frac{2\pi}{3}cos\frac{\pi}{3} + i^24i sin\frac{2\pi}{3}sin\frac{\pi}{3}    \\ab=8cos\frac{2\pi}{3}cos\frac{\pi}{3}+ 4i cos\frac{2\pi}{3}sin\frac{\pi}{3} + 2i sin\frac{2\pi}{3}cos\frac{\pi}{3} - 4i sin\frac{2\pi}{3}sin\frac{\pi}{3}

Note that i² = -1

Hence the required product of the function is 8cos\frac{2\pi}{3}cos\frac{\pi}{3}+ 4i cos\frac{2\pi}{3}sin\frac{\pi}{3} + 2i sin\frac{2\pi}{3}cos\frac{\pi}{3} - 4i sin\frac{2\pi}{3}sin\frac{\pi}{3}

Learn more here: brainly.com/question/9258225

8 0
3 years ago
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