Question

Someone help pls need help on this one

Answer 1

Answer:

$\dfrac{2}{3x^5y}$

Step-by-step explanation:

A negative exponent in the numerator is the same as a positive exponent in the denominator, and vice versa.

... a^-b = 1/a^b . . . . . for any value of b, positive or negative

The exponent of a product is the sum of the exponents:

... (a^b)(a^c) = a^(b+c)

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Applying these rules, you have

... = 2/(3x^4·x·y) = 2/(3x^(4+1)·y) = 2/(3x^5·y)