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gizmo_the_mogwai [7]
3 years ago
5

Someone help pls need help on this one

Mathematics
1 answer:
garri49 [273]3 years ago
5 0

Answer:

\dfrac{2}{3x^5y}

Step-by-step explanation:

A negative exponent in the numerator is the same as a positive exponent in the denominator, and vice versa.

... a^-b = 1/a^b . . . . . for any value of b, positive or negative

The exponent of a product is the sum of the exponents:

... (a^b)(a^c) = a^(b+c)

___

Applying these rules, you have

... = 2/(3x^4·x·y) = 2/(3x^(4+1)·y) = 2/(3x^5·y)

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The radius is 6 and the height is 15 what is the volume in terms of pi the shape is a cone
Alenkinab [10]

Answer:

565.49 or if rounded to the nearest tenth, 565.5

Explanation:

The formula for finding the volume of a cone is V=1/3Bh

B = pi times the radius squared

h = height

Substitute 6 for r and 15 for h.

V= 1/3·\pi·(6^{2})·15

Multiply.

V= 565.49 or 565.5 rounded to the nearest tenth.

4 0
3 years ago
Pliz answer this question
irina1246 [14]
Cent is by the hundred so one percent is 1/100 so .6%=6/1000
which can be reduced to 3/500
7 0
3 years ago
Please help for 10 points and i will pick the brainliest . Thankyou
lidiya [134]
23) Store A: y=6.30÷2
y=3.15
Store B: y=3.2
Store C: y=3.25x
y=3.25 so Store A sells the cheapest so (A) is the answer

24) the area uses half of the diameter, not the whole diameter. so the answer is 5.5pi^2 (B)

25) 1/2 × 1/2 = 1/4 × 1/2 = 1/8 (D)

26) was done correctly and (D) is the correct answer

27) 2 (x-3) +1 =19
2 (x-3) = 19 - 1
(x-3) = 18 ÷ 2
x-3 = 9
x= 9+3
x=12 (D)
4 0
3 years ago
Please help me
Inga [223]

Answer:

D

Step-by-step explanation:

All real numbers are solution

Step 1: Simplify both sides of the inequality.

8x−7<8x−3

Step 2: Subtract 8x from both sides.

8x−7−8x<8x−3−8x

−7<−3

Step 3: Add 7 to both sides.

−7+7<−3+7

0<4

hope this help:)

5 0
2 years ago
There are 75 balloons in each package. How many are in 20 packages
Oksana_A [137]

Answer:

1,500 balloons in 20 packages

Step-by-step explanation:

75 x 20 = 1500

5 0
3 years ago
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