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marysya [2.9K]
3 years ago
8

Please help!!!! I am about to fail !!

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

<u>Given:</u>

A circle with its center at (0, -3).

<u>To find:</u>

The standard equation for the given circle.

<u>Solution:</u>

The standard form of a circle is (x-h)^{2}+(y-k)^{2}=r^{2}, where (h, k) is the center of the circle and r is the radius of the circle.

The center of the given circle is at (0, -3).

We need to determine the radius of the circle. The center is at (0, -3) and a point with the same y coordinate is (3, -3).

The radius of the circle = 3-0=3 units.

So for the given circle, (h, k) is (0, -3) and r is 3 units.

So the equation becomes (x-0)^{2}+(y-(-3))^{2}=3^{2}.

The standard equation for the circle is x^{2}+(y+3)^{2}=9.

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