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Masteriza [31]
3 years ago
12

The magazine Sports Illustrated asked a random sample of 750 Division I college athletes, "Do you believe performance-enhancing

drugs are a problem in college sports?" Suppose that 30% of all Division I athletes think that these drugs are a problem. Let p^ be the sample proportion who say that these drugs are a problem.
Which of the following are the mean and standard deviation of the sampling distribution of the sample proportion p^?

a) Mean = 0.30, SD = 0.017
b) Mean = 0.30, SD = 0.55
c) Mean = 0.30, SD = 0.0003
d) Mean = 225, SD = 12.5
e) Mean = 225, SD = 157.5
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
3 0

Answer:

a) Mean = 0.30, SD = 0.017

Step-by-step explanation:

The mean and sampling distribution of the sample proportion can be found using the equations

Mean= p

SD=\sqrt{\frac{p*(1-p)}{n} }

where

  • n is the sample size (750)
  • p is the sample proportion of all Division I athletes think that these drugs are a problem (0.30 or 30%)

Using these information:

Mean = 0.30

SD=\sqrt{\frac{0.30*0.70}{750} } ≈ 0.017

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<h3>What is a function?</h3>

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The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

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