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3 years ago

14 bands volunteered but 7 played. How many lineups?

Mathematics

1 answer:

ankoles [38]3 years ago

8 0

Answer:

3432

Step-by-step explanation:

Total bands = 14

Bands played = 7

The possible lineups can be calculated using Combination.

So, the possible lineups are 14C7

=> $\frac{14!}{7!(14-7)!}$

=> 3432

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yanalaym [24]

$\huge {\mathfrak{Answer : }}$

we know,

$\boxed{\cos( \theta) = \dfrac{base}{hypotenuse}}$

so,

$\cos(30) = \dfrac{24}{x}$

$\dfrac{ \sqrt{3} }{2} = \dfrac{24}{x}$

$x = \dfrac{24 \times 2}{ \sqrt{3} }$

$x = 8 \sqrt{3} \times 2$

$x = 16 \sqrt{3}$

now,

$\boxed{ \tan( \theta) = \frac{perpendcular}{base} }$

$\tan(30) = \dfrac{y}{24}$

$\dfrac{1}{ \sqrt{3} } = \dfrac{y}{24}$

$y = \dfrac{24}{ \sqrt{3} }$

$y = 8 \sqrt{3}$

6 0

3 years ago

What is the result when 6x^3+25x^2+20x+46x

goldenfox [79]

Answer:

The answer to your question is 2x² - 29x + 26

Step-by-step explanation:

dividend = 6x³ - 25x² + 20x + 4

divisor = 3x + 2

2x² - 29x + 26

3x + 2 6x³ - 25x² + 20x + 4

-6x³ - 4x²

0 - 29x² + 20x

+ 29x² + 58x

0 78x + 4

-78x - 52

0 - 48

quotient = 2x² - 29x + 26

remainder = -48

Result = 2x² - 29x + 26 - 48/6x³ - 25x² + 20x + 4

6 0

3 years ago

What are four ways to represent functions?

telo118 [61]

A function can be represented verbally. For example, the circumference of a square is four times one of its sides.
A function can be represented algebraically. For example, 3x+6 3 x + 6 .
A function can be represented numerically.
A function can be represented graphically.

6 0

3 years ago

Read 2 more answers

The measure of B is (3x-4)° and the measure of D is (2x-6)°. What are the measures of angles B and D?

Ilia_Sergeevich [38]

Answer:

5x - 10

Step-by-step explanation:

→ Find the sum of the expression

3x - 4 + 2x - 6

→ Collect all the x terms

3x + 2x - 4 - 6

→ Simplify

5x - 10

3 0

2 years ago

Find the X-Intercepts of <br> y=-x^2-2x+1

bekas [8.4K]

Answer:

(1,0)

Step-by-step explanation:

we can't factor this so we'll use the quadratic formula

$\frac{-b+\sqrt{b^2-4ac} }{2a}\\\frac{-b-\sqrt{b^2-4ac} }{2a}$

(use both of them because usually there are two zeroes)

We have

$\frac{2+\sqrt{4-4}}{2}=\frac{2}{2}=1$

Therefore the x intercept is just (1,0)

6 0

3 years ago