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STatiana [176]
3 years ago
11

An assembly line has two inspectors. The probability that the first inspector will miss a defective item is 0.06. If the defecti

ve item passes the first​ inspector, the probability that the second inspector will miss it is 0.07. What is the probability that a defective item will pass by both​ inspectors?
Mathematics
1 answer:
Novay_Z [31]3 years ago
7 0

Answer:

probability that both passes a defective item is  0.8742‬

<h3>Step-by-step explanation:</h3>

probability that the first inspector misses is Pr( 1st misses)= 0.06

therefore the probability he does not miss is

Pr(1st passes)= 1 - Pr( 1st misses) = 1 - 0.06 = 0.94

probability that the second misses is Pr( 2nd misses) = 0.07

therefore probability that 2nd does not miss is

Pr( 2nd passes) = 1- Pr( 2nd misses) = 0.93

probability that both passes a defective item is  Pr(1st passes)*Pr( 2nd passes)

= 0.93*0.94 = 0.8742‬

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What number should go in box A on this number line? 4. 5. A​
cestrela7 [59]

Answer:

5

Step-by-step explanation:

4 0
2 years ago
I need help asap....................
docker41 [41]

Based on the given points, the point that is located on the y-axis is (0,7).

<h3>Which point is on the y axis?</h3>

The point that is on the y-axis should have a coordinate such that x is equal to 0.

This leads to the point being on the y-axis because the nonzero coordinate of the y axis would then have to be placed on the same axis.

The only point with a 0 coordinate is (0, 7) so this is the point that is located on the y-axis.

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7 0
2 years ago
Polynomial function in standard form with zeros 5,-4,1
Oksanka [162]

Answer:

\boxed{\sf \ \ \  x^3-2x^2-19x+20 \ \ \  }

Step-by-step explanation:

hello,

by definition we can write

(x-5)(x+4)(x-1)

as 5,-4,1 are the zeroes

now we have to write it in the standard form, let's do it

(x-5)(x+4)(x-1)=(x^2+4x-5x-20)(x-1)\\=(x^2-x-20)(x-1)=x^3-x^2-20x-x^2+x+20\\=x^3-2x^2-19x+20

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5 0
3 years ago
What is the value of R
frutty [35]

Answer:

2.45 × 10^{6}

Step-by-step explanation:

using the rules of exponents

• \frac{a^{m} }{a^{n} } = a^{(m-n)}

• (a^m)^{n} = a^{mn}

evaluating the numerator

(3.8 × 10^{5})² = 3.8² × (10^5)^{2} = 14.44 × 10^{10}

R = \frac{14.44.10^{10} }{5.9.10^{4} }

  = \frac{14.44}{5.9} × \frac{10^{10} }{10^{4} }

  = 2.45 × 10^{6} ← to 2 dec. places




7 0
3 years ago
I need an equation that equals 15, can't be one step
HACTEHA [7]
5*5-10=15 I hope this helps you
7 0
3 years ago
Read 2 more answers
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