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STatiana [176]
3 years ago
11

An assembly line has two inspectors. The probability that the first inspector will miss a defective item is 0.06. If the defecti

ve item passes the first​ inspector, the probability that the second inspector will miss it is 0.07. What is the probability that a defective item will pass by both​ inspectors?
Mathematics
1 answer:
Novay_Z [31]3 years ago
7 0

Answer:

probability that both passes a defective item is  0.8742‬

<h3>Step-by-step explanation:</h3>

probability that the first inspector misses is Pr( 1st misses)= 0.06

therefore the probability he does not miss is

Pr(1st passes)= 1 - Pr( 1st misses) = 1 - 0.06 = 0.94

probability that the second misses is Pr( 2nd misses) = 0.07

therefore probability that 2nd does not miss is

Pr( 2nd passes) = 1- Pr( 2nd misses) = 0.93

probability that both passes a defective item is  Pr(1st passes)*Pr( 2nd passes)

= 0.93*0.94 = 0.8742‬

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Answer:

She divided the coefficients incorrectly

Step-by-step explanation:

A. She divided the coefficients incorrectly.

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C. She divided the coefficients instead of subtracting them.

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Correct calculation:

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elena-s [515]
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