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Airida [17]
3 years ago
14

Jonathan purchased 4 shirts, 2 jackets, and 3 pants. How many different outfits using a

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
4 0

Answer:

24 way im pretty sure

Step-by-step explanation:

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A 300-page book is 10 inches long, 8 inches wide, and 3 4 inches tall. What is the volume of 100 pages of the book?
katen-ka-za [31]

Answer:

20 in³

Step-by-step explanation:

Volume of 300 pages:

10 × 8 × 3/4

When the no. of pages change, only the thickness of the book changes:

Volume = 10 × 8 × ¼

= 20 in³

5 0
3 years ago
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What is the 0.9 to the power of 2
GalinKa [24]

Answer:

.81

Step-by-step explanation:

3 0
3 years ago
store A offers successive discounts of 10% one week and 20% the second week. store B offers a one-time discount of 25% the secon
11111nata11111 [884]

The store which offers the greater discount is store B.

<h3>Discount</h3>

Store A:

First week = 10%

= 10/100

= 0.1

Second week = 20%

= 20/100

= 0.2

Total discount = (0.1 + 0.2) / 2

= 0.15

Store B:

25%

= 25/100

= 0.25

Therefore, the store which offers the greater discount is store B.

Learn more about discount:

brainly.com/question/7459025

#SPJ1

7 0
1 year ago
Determine if the function f is an exponential function. If so, identify the base. If not, why not? f(x) = 2^2x
const2013 [10]
Answer: c) The base is 2.

Reason: It is an exponential function because the variable (2) depends on the x.
3 0
3 years ago
Kristen invests $ 5745 in a bank. The bank 6.5% interest compounded monthly. How long must she leave the money in the bank for i
podryga [215]

Answer:

1. 10.7 years

2. 17.0 years

3. 2nd option

Step-by-step explanation:

Use formula for compounded interest

A=P\cdot \left(1+\dfrac{r}{n}\right)^{nt},

where

A is final value, P is initial value, r is interest rate (as decimal), n is number of periods and t is number of years.

In your case,

1. P=$5745, A=2P=$11490, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

11490=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},\\ \\2=(1.0054)^{12t},\\ \\12t=\log_{1.0054}2,\\ \\t=\dfrac{1}{12}\log_ {1.0054}2\approx 10.7\ years.

2. P=$5745, A=3P=$17235, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then


17235=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},

3=(1.0054)^{12t},

12t=\log_{1.0054}3,

t=\dfrac{1}{12}\log_{1.0054}3\approx 17.0\ years.

3. <u>1 choice:</u> P=$5745, n=12 (compounded monthly), r=0.065 (6.5%), t=5 years and A is unknown. Then

A=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12\cdot 5},\\ \\A=5745\cdot (1.0054)^{60}\approx \$7936.39.

<u>2 choice:</u> P=$5745, n=4 (compounded monthly), r=0.0675 (6.75%), t=5 years and A is unknown. Then

A=5745\cdot \left(1+\dfrac{0.0675}{4}\right)^{4\cdot 5},\\ \\A=5745\cdot (1.0169)^{20}\approx \$8032.58.

The best will be 2nd option, because $8032.58>$7936.39

5 0
2 years ago
Read 2 more answers
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