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Tomtit [17]
3 years ago
11

Sharad went to his friend's place on a motorcycle. When he started, the reading was 19,235 km. When he reached his friend's plac

e it was 19,301 km. How many km did sharad travel ?
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
5 0

Answer:

the number of km did sharad travel is 66 km

Step-by-step explanation:

The computation of the number of km did sharad travel is as follows:

= The km at his friend place - km when he started

= 19,301 km - 19,235 km

= 66 km

Hence, the number of km did sharad travel is 66 km

So, the same is to be considered by applying the given formula so that the correct distance could come

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PtichkaEL [24]

Answer:

34

Step-by-step explanation:

Straight lines are 180 degrees, so the angle inside of the triangle next to the 127, is 53 degrees. (180-127= 53)

So to find "x", we need to figure out what the full number is.

59+53 = 112.

180-112= 68.

Now that we have the degree of the full angle, we can make an equation to find x.

x*2 = 68

(Divide 2 from both sides to isolate the variable)

x = 34  

I hope this helped!

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3 years ago
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victus00 [196]
F = 41
E = 90
D = 49
from D to E is 55
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4 years ago
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A detective finds a victim of murder at 9 am. At that time, the temperature of the body is 90.3 degrees F. One hour later, the b
LekaFEV [45]

Answer:

Step-by-step explanation:

Given

at 9 am temperature of the body is 90.3^{\circ}F

1 hr later temperature 89^{\circ}F

Temperature of room T=68^{\circ}F

According to newtons law

\frac{\mathrm{d} T}{\mathrm{d} t}=-k\left ( T-T_{room}\right )

\frac{\mathrm{d} T}{\mathrm{d} t}=-k\left ( T-68\right )

\frac{dT}{T-68}=-kdt

Integrating

=\int \frac{dT}{T-68}=-kdt

\ln |T-68|=-kt+c

T-68=Ae^{-kt}

Now at 9 am i.e. t=0,

90.3=A+68

A=22.3

At 10 am i.e. t=1 hr T=89

89-68=22.3e^{-k}

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98.6-68=e^{-0.06006t}

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t=-5.27

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i.e. victim murdered at 3 am and 43.8 min

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