Rationalize the numerator:

This is continuous at
, so we can evaluate the limit directly by substitution:

Answer:
Step-by-step explanation:
Area of the trapezoid = area of rectangle + 2 * area of triangle
Area of a triangle = 1/2 bh
= 1/2 * 13 * 7
= 45.5 units²
Area of a rectangle = L × B
= 15 × 13
= 195 units²
Area of the trapezoid = [195 + 2 * (45.5)]
= 195 + 91
= 286 units²