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Vlad [161]
3 years ago
8

Given: A circle with inscribed quadrilateral ABCD

Mathematics
2 answers:
hammer [34]3 years ago
8 0

Step-by-step explanation:

m\angle BAD = \frac{1}{2} m(\overset {\frown} {BCD}) ... (1)\\

(By inscribed angle theorem)

m\angle BCD = \frac{1}{2} m(\overset {\frown} {BAD}) ... (2)\\

(By inscribed angle theorem)

Adding equations (1) & (2)

m\angle BAD+m\angle BCD \\= \frac{1}{2} m(\overset {\frown} {BCD}) +\frac{1}{2} m(\overset {\frown} {BAD}) \\\\= \frac{1}{2} (m\overset {\frown} {BCD} +m\overset {\frown} {BAD}) \\\\= \frac{1}{2}\times 360°\\\\= 180°\\\\\purple {\boxed {\bold {\therefore m\angle BAD+m\angle BCD =180°}}} \\\\\therefore \angle A \: and \: \angle C \: are \: supplementary\\

nadezda [96]3 years ago
8 0

Answer: a/2

Step-by-step explanation:

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Answer:

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54-28=26

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3 years ago
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3 0
3 years ago
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The graph below shows a proportional relationship between yyy and xxx.
Elena-2011 [213]

Answer:

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Step-by-step explanation:

Given

The attached graph

Required

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3 years ago
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