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Stella [2.4K]
3 years ago
15

Cx/d+f=b solve for x

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

\text{Hello there!}\\\\\text{Solve for x:}\\\\\frac{cx}{d}+f=b\\\\\text{Subtract f from both sides}\\\\\frac{cx}{d}=b-f\\\\\text{Multiply both sides by d}\\\\cx=d(b-f)\\\\cx=db-df\\\\\text{Divide both sides by c}\\\\x=\frac{db-df}{c}\\\\\boxed{x=\frac{db-df}{c}}

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A random sample of dogs at different animal shelters in a city shows that 8 of
jonny [76]

Answer:

224 puppies

Step-by-step explanation:

You would first divide 1,540 by 55 which would be 28

Then you would multiply 28 by 8 which is 224

So therefore there is 224 puppies in city's animal shelters

5 0
3 years ago
Does anyone know how to do this? I’m confused
nikklg [1K]

Answer:

cos(θ)

Step-by-step explanation:

Para una función f(x), la derivada es el límite de  

h

f(x+h)−f(x)

​

, ya que h va a 0, si ese límite existe.

dθ

d

​

(sin(θ))=(  

h→0

lim

​

 

h

sin(θ+h)−sin(θ)

​

)

Usa la fórmula de suma para el seno.

h→0

lim

​

 

h

sin(h+θ)−sin(θ)

​

 

Simplifica sin(θ).

h→0

lim

​

 

h

sin(θ)(cos(h)−1)+cos(θ)sin(h)

​

 

Reescribe el límite.

(  

h→0

lim

​

sin(θ))(  

h→0

lim

​

 

h

cos(h)−1

​

)+(  

h→0

lim

​

cos(θ))(  

h→0

lim

​

 

h

sin(h)

​

)

Usa el hecho de que θ es una constante al calcular límites, ya que h va a 0.

sin(θ)(  

h→0

lim

​

 

h

cos(h)−1

​

)+cos(θ)(  

h→0

lim

​

 

h

sin(h)

​

)

El límite lim  

θ→0

​

 

θ

sin(θ)

​

 es 1.

sin(θ)(  

h→0

lim

​

 

h

cos(h)−1

​

)+cos(θ)

Para calcular el límite lim  

h→0

​

 

h

cos(h)−1

​

, primero multiplique el numerador y denominador por cos(h)+1.

(  

h→0

lim

​

 

h

cos(h)−1

​

)=(  

h→0

lim

​

 

h(cos(h)+1)

(cos(h)−1)(cos(h)+1)

​

)

Multiplica cos(h)+1 por cos(h)−1.

h→0

lim

​

 

h(cos(h)+1)

(cos(h))  

2

−1

​

 

Usa la identidad pitagórica.

h→0

lim

​

−  

h(cos(h)+1)

(sin(h))  

2

 

​

 

Reescribe el límite.

(  

h→0

lim

​

−  

h

sin(h)

​

)(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)

El límite lim  

θ→0

​

 

θ

sin(θ)

​

 es 1.

−(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)

Usa el hecho de que  

cos(h)+1

sin(h)

​

 es un valor continuo en 0.

(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)=0

Sustituye el valor 0 en la expresión sin(θ)(lim  

h→0

​

 

h

cos(h)−1

​

)+cos(θ).

cos(θ)

5 0
3 years ago
Read 2 more answers
Examine the right triangle. What is the length of the hypotenuse, c? <br> Answers are in the pic
Olenka [21]

a^2+b^2=c^2 <----- the equation to find out sides for a right triangle

7 0
3 years ago
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The green object below,is best defined as a ___ named____.
notka56 [123]

Answer:

ray AC

Step-by-step explanation:

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6 0
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Mrs. Duggin walked every day for seven days. If she walked 9/10 of a mile each day for seven days, how many total miles did she
Molodets [167]

Answer:

Mrs. Duggin walked a total of \frac{63}{10} \ miles..

Step-by-step explanation:

Given:

Number of miles walked on each day = \frac{9}{10} \ mile

Number of days she walked = 7

We need to find the Total miles she walked using repeated addition method.

Solution:

Now we know that Repeated Addition means adding each group together and it is also known as Multiplication.

So we can Find Total miles she walked by adding Number of miles walked on each day with number of day times.

OR

we can Find Total miles she walked by Multiplying Number of miles walked on each day with number of days.

framing in equation form we get;

Total miles she walked = \frac{9}{10}+\frac{9}{10}+\frac{9}{10}+\frac{9}{10}+\frac{9}{10}+\frac{9}{10}+\frac{9}{10}= \frac{9+9+9+9+9+9+9}{10} = \frac{63}{10}\ miles

OR

Total miles she walked = \frac{9}{10}\times7= \frac{63}{10} \ miles.

Hence Mrs. Duggin walked a total of \frac{63}{10} \ miles..

4 0
4 years ago
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