Answer:
Step-by-step explanation:
I think the best way to do this is to find B using the cos law. The two other angles are equal
b = 3sqrt(3)
a = 3
c = 3
b^2 = a^2 + b^2 - 2ab*cos(B)
(3sqrt(3)^2 = 3^2 + 3^2 - 2*3*3 * cos(B)
27 = 9 + 9 - 18*cos(B)
27 = 18 - 18*cos(B)
9 = - 18*cos(B)
9/-18 = cos(B)
-1/2 = cos(B)
B = cos-1(-1/2)
B = 120
<A + <C + 120 = 180
<A = <C
2A + 120 = 180
2A = 60
A = 30
The question says angle A so that's what I did.
I hope it helps you get it right
Answer:
Step-by-step explanation:
Let
n------> the denominator of the quotient
we know that
Solve for n
X = -6 + y...so we sub in -6 + y for x in the other equation
x - 3y = 28
-6 + y - 3y = 28
-2y - 6 = 28
-2y = 28 + 6
-2y = 34
y = -34/2
y = - 17
x = -6 + y
x = -6 - 17
x = - 23
solution is (-23,-17)
Answer:
37 yw
Step-by-step explanation: