Answer:
![\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D)
Step-by-step explanation:
ok so first you want to find a common factor. For instance, 3. So divide the numerator and denominator by 3. This will give you the fraction of
.
Assuming John does not get premium pay for hours over 40, his pay will be ...
... 43 hours × $9.00 = $387
... - 6.2% × $387 = $23.99
... - 1.45% × $387 = $5.61
... - $15.00
... - 5% × $387 = $19.35
... - 10% × ($387 -19.35) = $36.77
... = $286.28 . . . . net pay after all the deductions
Answer:
a) 217
b) 1351
c) 5403
Step-by-step explanation:
Given that:
confidence interval (c) = 0.95
![\alpha =1-0.95=0.05\\\frac{\alpha }{2} =\frac{0.05}{2}=0.025](https://tex.z-dn.net/?f=%5Calpha%20%3D1-0.95%3D0.05%5C%5C%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%3D%5Cfrac%7B0.05%7D%7B2%7D%3D0.025)
The Z score of
is from the z table is given as:
![Z_{\frac{\alpha }{2} }=Z_{0.025}=1.96](https://tex.z-dn.net/?f=Z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%3DZ_%7B0.025%7D%3D1.96)
Range = $45000 - $30000 = $15000
The standard deviation (σ) is given as:
![\sigma=\frac{Range}{4} =\frac{15000}{4}=3750](https://tex.z-dn.net/?f=%5Csigma%3D%5Cfrac%7BRange%7D%7B4%7D%20%3D%5Cfrac%7B15000%7D%7B4%7D%3D3750)
Sample size (n) is given as:
![n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2](https://tex.z-dn.net/?f=n%3D%28%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%7D%7B2%7D%20%7D%5Csigma%7D%7BE%7D%20%29%5E2)
a) E = $500
≈ 217
b)
≈ 1351
c)
≈ 5403
Answer:
Step-by-step explanation:
Domain is all the x's and range is all the y's. There's no reason why you couldn't pop any x into the given equation and calculate it and get a number out. So literally ANY x can be used and found on this graph. So the domain is all real numbers, one of the first two answers is going to be the right one. Now, the range is all the y's on the graph. The problem says that the parabola opens down, which means it has a highest point. There is no graph above that point. That's the point (-1, 16). So 16 is the highest y-value you can find on the graph. All the rest of the y's are smaller. The range is all the y's such that the y's are 16 and smaller...in math that's written {y | y <= 16} So the second answer is the right one.
Solve x+4y = 13 for x by subtracting 4y from both sides.
We end up with x = -4y+13.
Since x and -4y+13 are the same, we can replace every x in the first equation with -4y+13
2x-3y = -29
2( x ) - 3y = -29
2( -4y+13 ) - 3y = -29 ... x is replaced with -4y+13
The answer is choice B