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2 years ago

Write an equation of a horizontal line passing through the two points (-2,-3) and (2,-3)

Mathematics

2 answers:

Marta_Voda [28]2 years ago

7 0

Answer:

Step-by-step explanation:

hello :

Use the point-slope formula.

y - y_1 = m(x - x_1)

m=0 ( horizontal line) and x_1 = 2 y_1 = -3

y-(-3) = 0(x-2)

y+3=0 is an equation

Olenka [21]2 years ago

4 0

Answer:

y = -3

Step-by-step explanation:

The first thing you should know is that a horizontal line always has a slope of 0. When the line is horizontal, the y coordinate never changes. So, your equation in slope intercept is:

y = -3

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Find the inverse function of y=(x-2)^2 + 3. please show steps

Lunna [17]

Answer:

$f^{-1}(x)=2\pm\sqrt{x-3}$

Step-by-step explanation:

we have

$y=(x-2)^2+3$

step 1

Exchange the variables (x for y and y for x)

$x=(y-2)^2+3$

Isolate the variable y

step 2

$x=(y-2)^2+3$

subtract 3 both sides

$(y-2)^2=x-3$

step 3

square root both sides

$y-2=\pm\sqrt{x-3}$

step 4

Adds 2 both sides

$y=2\pm\sqrt{x-3}$

step 5

Let

$f^{-1}(x)=y$

$f^{-1}(x)=2\pm\sqrt{x-3}$

8 0

3 years ago

13m +19 =14m m = what

dexar [7]

Answer: m = 19

Step-by-step explanation:

4 0

2 years ago

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(Geometry)

emmasim [6.3K]

M∠B = x
m∠A = 4x

x + 4x = 180
5x = 180
x = 180/5
x = 36

m∠B = x = 36°
m∠A = 4x = 4 * 36 = 144°

Answer is b. 144, 36

3 0

3 years ago

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Solve for x x ≡ 7 mod 11 answer is of the form x = a + bk where k is an integer

igor_vitrenko [27]

x=7+11k
This is fairly straigthforward if you know what mod is

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2 years ago

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mario62 [17]

Answer:

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2 years ago

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