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Serga [27]
3 years ago
6

1. Solve.

Mathematics
2 answers:
borishaifa [10]3 years ago
5 0

1. using the quadratic formula you get -9+/-sqrt(9^2-4*(1*2))/2*1

 this simplies to x = -9 +/- sqrt(73)/2

x = -0.22799812 and -8.77200187


2.  complex numbers have the letter i with them

 using the quadratic formula

 you get 0 +/- sqrt(0^2-4*(1*24))/2*1

x = -2i sqrt(6) and 2i sqrt(6)

s2008m [1.1K]3 years ago
4 0

Answer and explanation:

1) Solve : x^2+9x+2=0

Applying quadratic formula,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, a=1 , b=9, c=2

x=\frac{-9\pm\sqrt{9^2-4(1)(2)}}{2(1)}

x=\frac{-9\pm\sqrt{81-8}}{2}

x=\frac{-9\pm\sqrt{73}}{2}

x=\frac{-9+\sqrt{73}}{2},\frac{-9-\sqrt{73}}{2}

x=-0.227,-8.772

2) Given : x^2+24=0

To find : What is the solution of the equation when solved over the complex numbers?

Solution :

Quadratic equation, x^2+24=0

Subtract 24 both side,

x^2+24-24=-24

x^2=-24

Taking root both side,

x=\sqrt{-24}

x=\pm 2\sqrt{6}i

The solution of the equation is x=2\sqrt{6}i,-2\sqrt{6}i

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