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BaLLatris [955]

2 years ago

11

Solve for b A=h(a+b)2

2 answers:

White raven [17]2 years ago

5 0

Answer:

B = (A/(2h)) - a

Step-by-step explanation:

A = h(a+b)2

divide both sides of the equation by 2h

A/(2h) = a+b

subtract a from both sides

(A/(2h)) -a = b

Elanso [62]2 years ago

4 0

B=A/2h-a
Isolate the variable by dividing each side by factors that don’t contain the variable.

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Help! 144/360 reduced using prime factorization

kicyunya [14]

Divdie by 12
12/30
6/15

7 0

2 years ago

Which equation represents the given statement "Eight times a number minus 2 equals 33

Ivahew [28]

Answer:

8N-2=33+N

Step-by-step explanation:

4 0

3 years ago

Consider the following 8 numbers, where one labelled x is unknown. 4, 32, 6, x , 10, 3, 35, 37 Given that the range of the numbe

Natali [406]

Answer:

$\boxed{x=-27, \: x=67}$

Step-by-step explanation:

There can be two values of x.

The range is largest no. - smallest no.

Range = 64

Let x be the smallest no.

largest no. from the list is 37

37 - x = 64

-x = 64 - 37

x = -27

Let x be the largest no.

smallest no. from the list is 3

x - 3 = 64

x = 64 + 3

x = 67

8 0

2 years ago

Read 2 more answers

It is twice as far from (3,0) as it is from the y axis

DIA [1.3K]

(3,6). 3 units from point. 6 units from y axis.

4 0

2 years ago

Noel and Casey both start at the same place. Noel walks due south and Casey walks due east. After some time has passed, Noel is

Dovator [93]

Answer:

2.04 miles per hour

Step-by-step explanation:

Given

Noel

$n_1 =6miles$

$r_1 = 2mph$

Casey

$c_1 = 8miles$

$r_2 =1mph$

Required

The rate at which the distance increases

Their movement forms a right triangle and the distance between them is the hypotenuse.

At $n_1 =6miles$ and $c_1 = 8miles$

The distance between them is:

$d_1 = \sqrt{n_1^2 + c_1^2}$

$d_1 = \sqrt{6^2 + 8^2}$

$d_1 = \sqrt{100}$

$d_1 = 10miles$

After 1 hour, their new position is:

New = Old + Rate * Time

$n_2 = n_1 + r_1 * 1$

$n_2 = 6 + 2 * 1 = 8$

And:

$c_2 = c_1 + r_2 * 1$

$c_2 = 8 + 1 * 1 = 9$

So, the distance between them is now:

$d_2 = \sqrt{n_2^2 + c_2^2}$

$d_2 = \sqrt{8^2 + 9^2}$

$d_2 = \sqrt{145}$

$d_2 = 12.04$

The rate of change is:

$\triangle d = d_2 -d_1$

$\triangle d = 12.04 -10$

$\triangle d = 2.04$

5 0

2 years ago