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Helen [10]
3 years ago
12

The drama club is selling candles for a fundraiser. They spend $100 on the candles and sell them for $4.50 each. How many candle

s must they sell to make more than $125 profit? Let x represent the number of candles sold. Which inequality can you use to find x?
Mathematics
2 answers:
IrinaVladis [17]3 years ago
7 0
So we know that they spend $100 on the candles. In order to make a $125 profit, they must sell $225 worth of candles. Each candle sells for $4.50, so:
4.5x > 225 is the inequality for that. It just means $4.50 times the number of candles has to be more than the $225 we need. To simplify it, just divide both sided by 4.5:
x > 50
They have to sell more than 50 candles. Make sense?
DerKrebs [107]3 years ago
7 0

Its 4.5x – 100 > 125

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A local yoga studio
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Answer:

Let's call the first studio, yoga studio A.

Let's call the second studio, yoga studio B.

The equations:

Yoga Studio A: y=10x+55

Yoga Studio B: y=12.5x+25

So, for 12 classes:

Yoga Studio A: y=10(12)+55, y=175

Yoga Studio B: y=12.5(12)+25, y=175

These two numbers are equal, so Griffin is right.

For 10 classes:

Yoga Studio A: y=10(10)+55, y=155

Yoga Studio B: y=12.5(10)+25, y=150.

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b

Step-by-step explanation:

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How many cents are in $1
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Students who have completed a speed reading course have reading speeds that are normally distributed with a mean of 950 words pe
VikaD [51]

Answer:

36.04% probability that at most two of them would read at less than 850 words per minute

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the binomial probability distribution.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Percentage of students who read less than 850 words per minute.

Pvalue of Z when X = 850. The mean is \mu = 950 and the standard deviation is \sigma = 200

Z = \frac{X - \mu}{\sigma}

Z = \frac{850 - 950}{200}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

30.85 of students read less than 850 words per minute.

If 10 students are selected at random, what is the probability that at most two of them would read at less than 850 words per minute

This is P(X \leq 2) when n = 10, p = 0.3085. So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.3085)^{0}.(0.6915)^{10} = 0.0250

P(X = 1) = C_{10,1}.(0.3085)^{1}.(0.6915)^{9} = 0.1115

P(X = 2) = C_{10,2}.(0.3085)^{2}.(0.6915)^{8} = 0.2239

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0250 + 0.1115 + 0.2239 = 0.3604

36.04% probability that at most two of them would read at less than 850 words per minute

8 0
3 years ago
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