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podryga [215]
4 years ago
9

Angela took a general aptitude test and scored in the 91st percentile for aptitude in accounting. (a) What percentage of the sco

res were at or below her score?(b) What percentage were above?
Mathematics
1 answer:
BartSMP [9]4 years ago
8 0

Answer:

a) 91% of the scores were at or below her score.

b) 9% of the scores were above her score.

Step-by-step explanation:

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

In this problem, we have that:

Angela scored on the 91st percentile.

(a) What percentage of the scores were at or below her score?

Since Angela scored on the 91st percentile, 91% of the scores were at or below her score.

(b) What percentage were above?

Since Angela scored on the 91st percentile, 9% of the scores were above her score.

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Find the value of the length x rounded to 1 DP.
ivanzaharov [21]

Answer:

x = 13.6 cm

Step-by-step explanation:

part A:

using tan rule:

tan(x) = \frac{opposite}{adjacent}

tan(39) = \frac{6}{adjacent}

adjacent = \frac{6}{tan(39)}

adjacent = 7.41

part B:

using tan rule:

tan(x) = \frac{opposite}{adjacent}

tan(44) = \frac{6}{adjacent}

adjacent = 6.213

Total length of x:

part A + part B

7.41 + 6.213

13.6 cm

6 0
2 years ago
Read 2 more answers
The estimate of the population proportion should be within plus or minus 0.02, with a 90% level of confidence. The best estimate
Rudiy27

Answer:

The sample size required is 910.

Step-by-step explanation:

The confidence interval for population proportion is:

CI=\hat p\pm z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }

The margin of error is:

MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }

Given:

\hat p = 0.16\\MOE= 0.02\\Confidence\ level =0.90

The critical value of <em>z</em> for 90% confidence level is:

z_{\alpha /2}=z_{0.10/2}=z_{0.05}=1.645 *Use a standard normal table.

Compute the sample size required as follows:

MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }\\0.02=1.645\times \sqrt{\frac{0.16(1-0.16)}{n} }\\n=\frac{(1.645)^{2}\times 0.16\times (1-0.16)}{(0.02)^{2}} \\=909.2244\\\approx910

Thus, the sample size required is 910.

5 0
3 years ago
Two certificates of deposit pay interest at rates that differ by 4%. Money invested for one year in the first CD earns $175 inte
wolverine [178]
We are told that the principle is the same for both investments so we can say:

315=P(r+4)/100 and 175=Pr/100 solving both for P you have:

P=31500/(r+4) and P=17500/r since P=P:

17500/r=31500/(r+4)

175(r+4)=315r

175r+700=315r

-140r+700=0

-140r=-700

r=5

So the rates are 5% and (5+4)=9%

check...

P(9/100)=315  and P(5/100)=175

P=31500/9 and P=17500/5

P=157500/45 and P=157500/45

So P=P

note:  P=$3500

3500(9/100)=$315

3500(5/100)=$175
5 0
3 years ago
Brainliest for right answer! Help ASAP
Digiron [165]

Answer:

0/7 (no solutions)

Step-by-step explanation:

2 - 2 / 4 - (-3) = 0/7

4 0
4 years ago
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USE THE distance formula to solve.
Yuki888 [10]

Answer:

165 miles

Step-by-step explanation:

Multiply 55 x 3

4 0
3 years ago
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