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podryga [215]
3 years ago
9

Angela took a general aptitude test and scored in the 91st percentile for aptitude in accounting. (a) What percentage of the sco

res were at or below her score?(b) What percentage were above?
Mathematics
1 answer:
BartSMP [9]3 years ago
8 0

Answer:

a) 91% of the scores were at or below her score.

b) 9% of the scores were above her score.

Step-by-step explanation:

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

In this problem, we have that:

Angela scored on the 91st percentile.

(a) What percentage of the scores were at or below her score?

Since Angela scored on the 91st percentile, 91% of the scores were at or below her score.

(b) What percentage were above?

Since Angela scored on the 91st percentile, 9% of the scores were above her score.

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Answer:

Two equal sides = 14.4 inches each

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Step-by-step explanation:

a + b + c = 36

a = b

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then:

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a = 2*36/5

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a = 14.4

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a = b

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Check:

14.4 + 14.4 + 7.2 = 36

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3 years ago
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Step-by-step explanation:

in order to make a the subject of fomular , you will open the bracket first and then combine the like terms.

G(a + h) = M

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Ga = M - Gh

since G is disturbing a from standing alone, we divide both sides by G

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Answer:-1>p

Step-by-step explanation:

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Divide by 3 on each side

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2 years ago
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