Answer:
Option (C) n = 256
Therefore, there are 256 ways to select a car with 2 car models, 8 different colors and any combinations of 4 optional features.
Step-by-step explanation:
A new car is available in a sedan model and a hatchback model.
So that means customers can select the model of the car in,
n₁ = 2 ways
It is available in eight different colors.
After selecting the model, customers can select the color of the car in,
n₂ = 8 ways
Customers can choose to add any combination of four optional features.
After selecting the color, customers have the choice to add any combination of 4 optional features,
n₃ = 4² = 16 ways
Which means that there are 16 different ways to add 4 optional features e.g.
1. 0, 0, 0, 0
2. 0, 0, 0, 1
3. 0, 0, 1, 0
4. 0, 0, 1, 1
and the list goes on to 16 different ways.
Now the total ways to select a car is given by
n = n₁*n₂*n₃
n = 2*8*16
n = 256
Therefore, there are 256 ways to select a car with 2 car models, 8 different colors and any combinations of 4 optional features.
Answer:
Since the pvalue of the test is 0.2743 > 0.1, the threshold probably was met.
Step-by-step explanation:
The widget manufacturing company had established a threshold of 60% preferring the proposed new widget to move forward with producing the new widgets.
This means that at the null hypothesis we test if the proportion is at least 60%, that is:
![H_{0}: p \geq 0.6](https://tex.z-dn.net/?f=H_%7B0%7D%3A%20p%20%5Cgeq%200.6)
And the alternate hypothesis is:
![H_{a}: p < 0.6](https://tex.z-dn.net/?f=H_%7Ba%7D%3A%20p%20%3C%200.6)
The test statistic is:
![z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
0.6 is tested at the null hypothesis:
This means that:
![\mu = 0.6](https://tex.z-dn.net/?f=%5Cmu%20%3D%200.6)
![\sigma = \sqrt{0.6*0.4}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B0.6%2A0.4%7D)
Three hundred thirty-eight of 575 respondents reported preferring the proposed new widget.
This means that ![n = 575, X = \frac{338}{575} = 0.5878](https://tex.z-dn.net/?f=n%20%3D%20575%2C%20X%20%3D%20%5Cfrac%7B338%7D%7B575%7D%20%3D%200.5878)
Value of the test-statistic:
![z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
![z = \frac{0.5878 - 0.6}{\frac{\sqrt{0.6*0.4}}{\sqrt{575}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B0.5878%20-%200.6%7D%7B%5Cfrac%7B%5Csqrt%7B0.6%2A0.4%7D%7D%7B%5Csqrt%7B575%7D%7D%7D)
![z = -0.6](https://tex.z-dn.net/?f=z%20%3D%20-0.6)
Pvalue of the test and decision:
We want to find the probability of a proportion of 0.5878 or lower, which is the pvalue of z = -0.6.
Looking at the z-table, z = -0.6 has a pvalue of 0.2743.
Since 0.2743 > 0.1, the threshold probably was met.
x = 2(180 - x) - 12
3x = 348
x = 116
The measure of the angle is 116 degrees.
Answer:
-6p^5+48p
Step-by-step explanation:
-6p (p^4- 8)= -6p^5+48p