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Dafna1 [17]
3 years ago
9

Multiple-choice questions each have 6 possible answers, one of which is correct. Assume that you guess the answers to 5 such que

stions. Use the multiplication rule to find the probability that the first four guesses are wrong and the fifth is correct. That is, find P ( W W C ) P(X C), where C denotes a correct answer and W denotes a wrong answer.
Mathematics
1 answer:
ikadub [295]3 years ago
6 0

Answer:

etktk

Step-by-step explanation:

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Solve 6 1/2 + 7 3/8 - 6 1/2
Amiraneli [1.4K]

Answer:

Step-by-step explanation:

6 1/2 - 6 1/2 + 7 3/8 =

0 + 7 3/8 = 7 3/8

3 0
3 years ago
Which expression is equivalent to 5x + 7y?
Reptile [31]

Answer:

that would be "b"

Step-by-step explanation:

The commutative property says that a + b = b + a so the correct answer is 7y +5x.

3 0
4 years ago
The table below shows the radius y, in inches, created by growing algae in x days: Time (x) (days) 1 4 7 10 Radius (y) (inches)
tatuchka [14]
PART A:
Given the table below showing the radius y, in inches, created by growing algae in x days.

Time (x) (days):          1       4        7        10
Radius (y) (inches):    1       8       11       12

We can find the find the correlation coeficient of the data using the table below:
\begin{center}
\begin{tabular}
{|c|c|c|c|c|}
x & y & x^2 & y^2 & xy \\ [1ex]
1 & 1 & 1 & 1 & 1\\
4 & 8 & 16 & 64 & 32\\
7 & 11 & 49 & 121 & 77\\
10 & 12 & 100 & 144 & 120\\ [1ex]
\Sigma x=22 & \Sigma y=32 & \Sigma x^2=166 & \Sigma y^2=330 & \Sigma xy=230
\end{tabular}
\end{center}

Recall that the correlation coefitient is given by the equation:
r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{ \sqrt{(n\Sigma x^2-(\Sigma x)^2)(n\Sigma y^2-(\Sigma y)^2)} }  \\  \\ = \frac{4(230)-(22)(32)}{ \sqrt{(4(166)-(22)^2)(4(330)-(32)^2)} } = \frac{920-704}{ \sqrt{(664-484)(1,320-1,024)}}  \\  \\ = \frac{216}{ \sqrt{180(296)}} = \frac{216}{ \sqrt{53,280} } = \frac{216}{230.8} =0.94

[Notice: even without using the formular to find the value of the correlation coeficient, it can be seen that the value of y strictly increases as the valu of x increases. This means that the value of the correlation coeficient is closer to +1 and from the options the value that is closest to +1 is 0.94]

From the value of the correlation coeffeicient, it can be deduced that the radius of the algae has a strong positive relationship with the time.

Recall the for the value of the correlation coeficient closer to +1, the relationship is strong positive, for the value closer to -1, the value is strong negative and for the values closer to zero, either way of zero is a weak positive if it is positive and weak negative if it is negative.


PART B:
Recall that the slope of a straight line passing through two points
(x_1,y_1) and (x_2,y_2)
is given by
m= \frac{y_2-y_1}{x_2-x_1}

Thus the slope of the graph of radius versus time between 4 and 7 days, [i.e. the line passes through points (4, 8) and (7, 11)] is given by
m= \frac{11-8}{7-4}= \frac{3}{3} =1

The value of the slope means that the radius of the algea grows by 1 inch evry day between day 4 and day 7.


PART C:
We can say that the data above represent both correlation and causationg.

Recall that correlation expresses the relationship between two variables while causation expresses that an event is as a result of another event.

From the information above, we have seen that there is a relationship (correlation) between the passing of days and the growth in the radius of the algae.

Also we can conclude that the growth in the radius of algae is a function of the passing of days, i.e. the growth in the radius of algae is as a result of the passing of days.

Therefore, <span>the data in the table represent both correlation and causation.</span>
6 0
3 years ago
Is this a function? Need halo on how to solve it
raketka [301]

Answer:

Yes it is because it is a straight line.

(I hope it helps, because i'm just learning about this meself so...)

5 0
3 years ago
I’m what quadrant does theta lie if the following statements are true? Sec(theta)&lt;0 and (sec (theta) )(csc (theta) ) &gt; 0
viktelen [127]

Because the cosine and sine must be negative when evaluated in theta, the angle lies on the third quadrant.

<h3>In which quadrant is the endpoint of the segment that defines the angle?</h3>

We know that if:

  • cos(θ) > 0, then we are on the first or fourth quadrant
  • sin(θ) > 0, then we are on first or second quadrant.

Here we know that:

sec(θ) < 0

And we know that:

sec(θ)  = 1/cos(θ)

Then we have cos(θ) < 0

We also have that:

sec(θ)*csc(θ) > 0

Because sec(θ) < 0, we must have that csc(θ) < 0.

Remember: csc(θ) = 1/sen(θ)

Then sen(θ) < 0.

Then we have the two conditions:

sen(θ) < 0

cos(θ) < 0

  • The cosine is negative on the third and second quadrants.
  • The sine is negative on the third and fourth quadrants.

The only quadrant where both are negative is the third quadrant, so that is the correct option.

If you want to learn more about trigonometric functions:

brainly.com/question/8120556

#SPJ1

6 0
2 years ago
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