Answer:
21 animals in the forest
Step-by-step explanation:
The weasel
Felicity
The 19 other animals
Hope this helped
Answer:
Let's solve your system of equations by elimination.
8x+9y=48;12x+5y=21
Steps:
Multiply the first equation by 5,and multiply the second equation by -9.
5(8x+9y=48)
−9(12x+5y=21)
Becomes:
40x+45y=240
−108x−45y=−189
Add these equations to eliminate y:
−68x=51
Then solve−68x=51for x:
−68x
/−68
=
51
/−68 (Divide both sides by -68)
x= −3
/4
Now that we've found x let's plug it back in to solve for y.
Write down an original equation:
8x+9y=48
Substitute
−3
/4
8x+9y=48:
8(
−3
/4
)+9y=48
9y−6=48 (Simplify both sides of the equation)
9y−6+6=48+6 (Add 6 to both sides)
9y=54
9y
/9 = 54
/9 (Divide both sides by 9) y=6
<em><u>Answer: x= −3
/4 and y=6</u></em>
Hope This Helps! Have A Nice Day!!
Answer:
Each student gets 11 pieces.
Step-by-step explanation:
80 ÷ 7 = 11.42857
80 divided by 7 comes out to a decimal therefore, you will have a remainder. 7 × 11 = 77
The answer would be 11 remainder 3.
At θ = 90°, the equation must evaluate to zero. The only one that does that is the 1st choice ...
r = 2 - 2sin(θ)
Answer:
f(x) = (1/2)(x-2)^2(x+1)(x+2)
Step-by-step explanation:
You can determine this by looking at the zeroes of the graph. For any zero that goes through the x-axis, the power of that zero is odd. For any zero that that "bounces" from the x-axis, the power of that zero is even.
Starting from left to right, we can see that the first zero, -2, goes through the x-axis. That means (x+2) is raised to an odd power. The second zero, -1, also goes through, so (x+1) is raised to an odd power. The last zero, 2, bounces off the x-axis, so (x-2) is raised to an even power. The only functions that satisfy this criteria are function 1 and 2.
However, we are not done yet. We need to figure out which multiplier value (1/2, 1/4) is correct. To do this, we plug in 0 for x, since we know that the y-intercept is 4. When we plug in 0, we see that f(0) = 4 for the first function. Therefore, the first function is the answer.
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