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VladimirAG [237]
3 years ago
12

You buy 8 books for $44. Paperbacks are $4 and hardbacks are $8. How many of each type can you buy?

Mathematics
2 answers:
Alika [10]3 years ago
6 0
She purchased 5 paperbacks at $4 and 3 hardbacks at $8 for a total of $44.

h = number of hardback books
p = number of paperback books
h + p = 8
so
h = 8-p
.
4*p = price of paperbacks
8*h = price of hardbacks
4*p + 8*h = 44
.
substitute h = 8-p
.
4p + 8(8-p) = 44
4p +64 -8p = 44
-4p = -20
p = 5
h = 8-p
h = 3
.
check to be sure the values are right
4*5 = 20
3*8 = 24
20 +24 = 44
Aleksandr-060686 [28]3 years ago
3 0

Answer:

She purchased 5 paperbacks at $4 and 3 hardbacks at $8 for a total of $44.

Step-by-step explanation:

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