Answer:
− 5 x − 16
Step-by-step explanation:
-2*x and -2*4= -2x+-8
-2x+3x= -5x
-8-8= -16
-5x-16
Answer:
2A/b
Step-by-step explanation:
A=1/2(b)(h)
2A=(b)(h) Multiply both sides by 2
2A/b=h Divide both sides by b
h=2A/b
P'(-3,-8) Q'(-6,4) R'(1,-1)
This should be correct! Hope I helped!
Answer:
<u>Option </u><u>D</u> (y = 5/6x -12).
Step-by-step explanation:
Hey there!
The equation of the line which passes through the point (12,-2) is (y+2) = m2(x-12)………(i) [Using one point formula].
According to the question, the first line passes through point (12,6) and (0,-4).
So,



Therefore, the slope of the line is 5/6.
Now as per the condition of parallel lines, m1 =m2 = 5/6.
So, keeping the value of m2 in equation (i), we get;
(y+2) = 5/6(x-12)

or, y = 5/6x - 12.
Therefore, the required equation is y = 5/6 X - 12.
<u>Hope</u><u> </u><u>it </u><u>helps</u><u>!</u>
Answer:

Step-by-step explanation:
Given



Required
Determine the coordinates of P
The coordinate of a point when divided into ratio is:

Where



This gives:



