Answer:
The degrees of freedom is 11.
The proportion in a t-distribution less than -1.4 is 0.095.
Step-by-step explanation:
The complete question is:
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion
Solution:
The information provided is:
Compute the degrees of freedom as follows:
Thus, the degrees of freedom is 11.
Compute the proportion in a t-distribution less than -1.4 as follows:
*Use a <em>t</em>-table.
Thus, the proportion in a t-distribution less than -1.4 is 0.095.
Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose
We have and , because the dice are fair.
Now we use the assumption of independence to claim that
Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:
- 2 in a unique way (1+1)
- 3 in two possible ways (1+2, 2+1)
- 4 in three possible ways
- 5 in three possible ways
- 6 in three possible ways
- 7 in two possible ways
- 8 in a unique way
This implies that the probabilities of the outcomes of are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5
X^m means x times itself m times
(-6)^5 means -6 time itself 5 times
simplify it says
remember that
(mn)^x=(m^x)(n^x)
undistribute the -1
(-6)^5=(-1)^5 times (6^5)
(-1)^5=-1 since it is odd power
can be simplified to
-6^5
(note, -6^5 vs (-6)^5 PEMDAS)
9514 1404 393
Answer:
7 pizzas
Step-by-step explanation:
For a difference in price of $58 -25 = $33, a customer gets a difference in number of 5 -2 = 3 pizzas. Then a pizza costs $33/3 = $11.
The cost of 2 pizzas is $22, so the delivery charge is $25 -22 = $3.
For $80, after subtracting the $3 delivery charge, $77 goes to the cost of pizzas. For that amount, $77/$11 = 7 pizzas will be delivered.
Ascending order just means to be arranged from smallest to largest
Answer: 1/6 2/3 3/5