Which is the slowest reading rate?

Please help me with this math problem!! :) Will give BRAINLIEST!! :)

Kitty [74]

The rate of change will be positive and a point in the graph will be (1,250);
the function then would be y = 250x;
after 1 year she will owe USD 5,250;
she will have to make 33 payments.

How to form equation using slope and one point?
y - y1 = m(x - x1) is the equation of a straight line's point slope form, where m is the line's slope and (x1, y1) is the point through which the provided line passes.

Using slope-point equation, the equation for the payment can be taken as:
y-250 = [(500-250)/(2-1)]*(x-1)
y - 250 = 250*(x-1)
y = 250 + 250x - 250 = 250x;
Putting x = 12, for a year the amount paid is USD 3,000.
Amount she owes = USD (8250-3000) = USD 5,250;
Total amount to be paid (in USD) = 8250
Amount paid per month (in USD) = 250
Thus, number of payments required = 8250/250 = 33

Thus, the rate of change will be positive and a point in the graph will be (1,250); the function then would be y = 250x; after 1 year she will owe USD 5,250; she will have to make 33 payments.

To learn more about slope point equation form tap on the link below:
brainly.com/question/24907633

#SPJ1

7 0

1 year ago

Is this True or False ?

Svetradugi [14.3K]

Answer:

Option B True

Step-by-step explanation:

we know that

A function relates <u>each element</u> of a set (input) with <u>exactly one</u> element of another set (output)

1) "...each element..." means that every element in X (input) is related to some element in Y (output)

2) "...exactly one..." means that a function is single valued. It will not give back 2 or more results for the same input

therefore

f(x) is a function

6 0

3 years ago

Use the Normal model N(1133,78) for the weights of steers.

Rudiy27

Answer:

Step-by-step explanation:

Let $X\sim N(1133, 78)$ .

Here, the mean is 1133 and standard deviation is 78.

Since we don't have the table for N(1133, 78), so we use the standard table for N(0,1),

a)

All we have to do is find, within the table the specific percentile.

now to find (42nd percentile) 0.42 in the normal table N(0,1) and extract the number on the row and column.

$P(X\leq x)=0.42$

Using: $Z=\frac{X-\mu}{\sigma}$ where $\mu$ is the mean and $\sigma$ is the standard deviation.

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.42$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.42$

Now, using Standard Normal table to find the value of z- score;

Usually, tables are set up as the probability that a number, z is less than or equal to Z.

i.e, $z= -0.20$

Now, putting this value in $z=\frac{x-1133}{78}$ , to find x;

$\frac{x-1133}{78}=-0.20$

On Simplify, we get;

$x=1,117.4$ pounds

b)

Similarly, find the weight for 91st percentile.

Follow the same steps that we have done in part (a),

$P(X\leq x)=0.91$ or

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.91$

⇒ $P(Z \leq \frac{x-1133}{78})=0.91$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.91$

Now, use normal table value to find the z-score;

Usually, tables are set up as the probability that a number, z is less than or equal to Z

we have, z= 1.34

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=1.34$

On simplify, we get

x= 1,237.52 pounds

c)

the interquartile range (IQR)=3rd Quartile - 1st quartile

First find the 1st quartile:

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.25$

⇒ $P(Z \leq \frac{x-1133}{78})=0.25$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.25$

Now, we use normal table to find that z=-0.675

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=-0.675$

On simplify, we get

x= 1,080.35 pounds

Similarly, for third quartile

By symmetry z=0.675

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=0.675$

On simplify, we get

x= 1,185.65 pounds

then, IQR = 1185.65 -1080.35=105.3 pounds

7 0

3 years ago

A random sample of 10 subjects have weights with a standard deviation of 13.5620 kg. What is the variance of their weights? Be

Iteru [2.4K]

Answer:

183.927844 kg²

Step-by-step explanation:

Calculation for the weight variance:

Given that s =13.5620 kg

The Variance will be the square of the Standard Deviation

S²=13.5620 kg²

S²=183.927844

The units of the variance will be the units of the Standard Deviation Squared which is Kg²

Therefore the variance of their weight will be:

183.927844 kg²

3 0

3 years ago

Can i not have the interactive ads

Lunna [17]

Press the x in the top :)

7 0

3 years ago