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3 years ago

Can anyone help me on this question please.

Mathematics

1 answer:

STatiana [176]3 years ago

5 0

The answer is 72.
You can figure this out using the Pythagorean theorem: C (78) squared - A (30) squared = B squared though since you already know the longest side.
78 x 78 = 6084
30 x 30 = 900
6084-900= 5184
The square root of 5184 is 72.

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1. Write 1/5 as a decimal

bija089 [108]

Answer:

1.5

1.5%

10/0

7/20

35.1%

8.20%

8.20

Step-by-step explanation:

there u go

7 0

3 years ago

This is a not graded question Help!

kogti [31]

The answer is B lm 100% sure

7 0

3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

Number 30, please help

GREYUIT [131]

Answer:

correct

Step-by-step explanation:

Imagine a point in the top left quadrant of a graph

when you rotate it 180 degrees it will end up in the bottom right quadrant

The same will apply if you flip on the y axis and the x axis in no given order

3 0

3 years ago

Read 2 more answers

Plot the point first and then use the slope from that point (-4,3) M=-1/2

Goshia [24]

Plot the point first and then use the slope from that point - 3270801. ... Plot the point first and then use the slope from that point (-4,3) M=-1/2. 0

7 0

3 years ago

Can anyone help me on this question please.​

Can anyone help me on this question please.