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Salsk061 [2.6K]
2 years ago
14

-2,-1,0,1 whichave pair of numbers has a sum of zero

Mathematics
1 answer:
Verizon [17]2 years ago
3 0
-1+1=0. So your answer is -1 and 1
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b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
3 years ago
Points are usually labeled as:
Alex73 [517]

Answer: a capital letter

Explanation: The most basic figure in geometry is called a point.

For example, ·A or ·Q.

Notice that above, points are usually labeled with a capital letter.

8 0
3 years ago
What is the value of (8 – 5)!?
Lubov Fominskaja [6]
<span>(8-5)!=3!=6</span>
7 0
3 years ago
What is the length of arc QR? <br> A. 1/3 π<br> B. 10/3 π<br> C. 5/3 π<br> D. 20/3 π
podryga [215]
D. 20/3 I think it’s the answe
3 0
3 years ago
If SAT scores are normally distributed with a mean of 1518 and a standard deviation of 325, find the probability that a randomly
aliya0001 [1]
Mean, x_bar = 1518
Standard deviation, sigma = 325
Range required: 1550 ≤ X ≤ 1575

Z = (X - x_bar)/sigma

Z1 = (1550-1518)/325 ≈ 0.1
Z2 = (1575-1518)/325 ≈ 0.18

From Z tables,
P(Z1) = 0.5398
P(Z2) = 0.5714

P(1550≤X≤1575) = P(Z2) - P(Z1) = 0.5714 - 0.5398 = 0.0316

The correct answer is C.
3 0
3 years ago
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