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Salsk061 [2.6K]
3 years ago
14

-2,-1,0,1 whichave pair of numbers has a sum of zero

Mathematics
1 answer:
Verizon [17]3 years ago
3 0
-1+1=0. So your answer is -1 and 1
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What is 6-2p=p+9 ?Because I don't know it​
nikklg [1K]

Hey there!

  • Firstly, you have to \bold{simplify} each of the sides of your equation
  • \bold{6-2p-p+9\downarrow}
  • \bold{6+(-2p)=p+9\downarrow}
  • \rightarrow\bold{-2p+6=p+9}
  • Now that you have that  portion out of the way, we could  move on to our second step... which is to \bold{subtract} by the value of  \bold{p} on each of your sides
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  • \rightarrow\bold{-3p+6-9} (you get this because we solve the particular equation we added above)
  • Thirdly, you have to \bold{subtract} by the number \bold{6} on each of your sides
  • \bold{-3p+6-6=9-6\downarrow}
  • \bold{Cancel:6-6} because it equals to \bold{0}
  • \bold{Keep:9-6} because it brings us closer and closer to the answer of \bold{p}
  • Fourthly, we have to \bold{divide} by  the number \bold{-3} on each of your sides
  • \bold{\frac{-3p}{-3}=\frac{3}{-3}}
  • \boxed{\boxed{\bold{Answer:p=-1}}} \checkmark

Good luck on your assignment and enjoy your day!

~\frak{LoveYourselfFirst:)}

8 0
4 years ago
The general form of the equation of a circle is Ax2 + By2 + Cx + Dy + E = 0, where A = B 0. If the circle has a radius of 3 unit
Anettt [7]
(x-h)^2 + (y-k)^2 = r^2

r=3
(x-h)^2 + (y-k)^2 = 3^2

the center lies on the y-axis --> h=0
x^2 + (y-k)^2 = 3^2 = 9

expand
x^2 + y^2 -2ky + k^2 = 9

x^2 + y^2 -2ky + (k^2 - 9) = 0
compare to general form
A=1 , B=1 and C =0
D= -2k and E=k^2 - 9
8 0
3 years ago
Read 2 more answers
Is 64^2−48+9 a perfect square trinomial?
Marysya12 [62]

Answer:

yes, it is a perfect square trinomial because the square of binomial are (x-0.375) (x-0.375)

5 0
3 years ago
PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B
Ivanshal [37]

Answer:

Your answer would be B

Step-by-step explanation:

a way to remember it is:

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5 0
3 years ago
If n is the term, what is the first integer value of n where the sequence 2n² is greater than 50?
Nezavi [6.7K]

Answer:

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Step-by-step explanation:

2n^2 sequence:

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3 0
3 years ago
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