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Maurinko [17]
3 years ago
9

Evaluate 5x²-4 when x = 3

Mathematics
2 answers:
krek1111 [17]3 years ago
3 0
5(3)^2-4
5(9)-4
45-4
41
kakasveta [241]3 years ago
3 0
5(3²) - 4
Simplify the exponent.
5(9) - 4
Distribute the 5 into 9
45 - 4
41

Your answer is 41

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1. Find 3 consecutive integers whose sum is 33.
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Answer: 10, 11, 12

Step-by-step explanation: Think of the integers like this:

1st integer: x

2nd integer: x+1

3rd integer: x+2

That is necessary because they are consecutive integers. Since the sum is 33, we need to create an equation.

x+x+1+x+2=33.

Simplify:

3x+3=33.

Opposite operations:

3x=-3+33.

To get the 3 close to the 33, we needed to make it negative, which is the opposite operation of the positive 3.

So,

3x=30.

Divide by 3:

x=10.

The first integer, x, equals 10.

To go with the guide that we already created,

1st integer: x=10

2nd integer: x+1=11

3rd integer:x+2=12.

Therefore, the three consecutive integers are 10, 11, and 12.

To check that, add them up. They all equal 33 and they are consecutive, which means this is the right answer!

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3 years ago
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