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3 years ago

What is 9x+12y ._. so can you help me ?? ...umm :p

Mathematics

1 answer:

Viefleur [7K]3 years ago

6 0

Simplifying

9x = 12y

Solving

9x = 12y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '9'.

x = 1.333333333y

Simplifying

x = 1.333333333y

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Use calculator to find the values of the following,correct to 3decimal places:<br><br> 1. Cot 61,4

g100num [7]

No such thing as cot (61,4). I think you meant to say cot (61.4°). See the difference?

So, cot (61.4°) is approximately -0.139844.

Rounded to 3 decimal places we get -0.140.

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3 years ago

What is the answer to number 1.<br><br>Please explain answer and show working out. Thanks

vagabundo [1.1K]

Answer:

3(4y+5b)

Step-by-step explanation:

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2 years ago

Based on a poll, 867 of 1050 randomly selected adult said that they always wear seat belts. Construct and interpret a 97% confid

Mekhanik [1.2K]

The 97% confidence interval for the proportion of adults is 0.801<P<0.851.

Given that 867 adults are randomly selected from 1050 who always wear seat belts.

A confidence interval refers to the probability that a population parameter will fall between a set of values for a certain proportion of times.

Let's assume n=1050 and x=867

Find the sample proportion by dividing the given proportion with sample size as,

$\begin{aligned}\hat{p}&=\frac{x}{n}\\\hat{p}&=\frac{867}{1050}\\ \hat{p}&=0.826 \end$

Find the α by subtracting the given confidence interval that is 97% from 1 as

α=1-(97÷100)

α=1-0.97

α=0.03

To find the critical value that is $Z_{\frac{\alpha}{2}}$ by dividing alpha with 2,

$\begin{aligned}Z_{\frac{\alpha}{2}}&=Z_{\frac{0.03}{2}}\\ Z_{\frac{\alpha}{2}}&=Z_{0.015}\end$

From this table which is shown in the figure it says that the critical value is

$Z_{crit}=\pm 2.17$

Use this formula to find the confidence interval $P=\hat{p}\pm Z_{Crit}\times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$

Substitute the values in the formula,

$\begin{aligned}P&=0.826\pm 2.17\times \sqrt{\frac{0.826(1-0.826)}{1050}}\\ P&=0.826\pm 2.17\times \sqrt{\frac{0.826\times 0.174}{1050}}\\ P&=0.826\pm 2.17\times 0.0116995\\ P&=0.826\pm 0.025\end{aligned}$

Hence, a 97% confidence interval for the proportion of adults who always wear seat belts is 0.801<P<0.851.

Learn more about confidence interval from here brainly.com/question/13929861

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2 years ago

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Vlada [557]

The circle is divided into 10 pieces, therefore 2 pieces are shaded, it being 2/10 of the circle shaded. 2/10 is also 20% of the shaded circle. Hope that helped

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Answer:

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