Answer:
15 kg
Step-by-step explanation:
Radius of a solid sphere : mass of a solid sphere
3 cm : 9 kg
Find the mass of a sphere of the same material of radius 5 cm
Radius of a solid sphere : mass of a solid sphere
5 cm : x kg
Equate both ratios to find x
3 cm : 9 kg = 5 cm : x kg
3/9 = 5/x
3 * x = 9 * 5
3x = 45
x = 45/3
x = 15 kg
The mass of a sphere of the same material of radius 5 cm is 15 kg
Given:
The table of values is
Number of Students : 7 14 21 28
Number of Textbooks : 35 70 105 140
To find:
The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.
Solution:
The ratio of number of textbooks to number of students are
![\dfrac{35}{7}=5](https://tex.z-dn.net/?f=%5Cdfrac%7B35%7D%7B7%7D%3D5)
![\dfrac{70}{14}=5](https://tex.z-dn.net/?f=%5Cdfrac%7B70%7D%7B14%7D%3D5)
![\dfrac{105}{21}=5](https://tex.z-dn.net/?f=%5Cdfrac%7B105%7D%7B21%7D%3D5)
![\dfrac{140}{28}=5](https://tex.z-dn.net/?f=%5Cdfrac%7B140%7D%7B28%7D%3D5)
All the ratios of the two quantities are proportional and equivalent to the unit rate.
Let y be the number of textbooks and x be the number of students, then
![\dfrac{y}{x}=k](https://tex.z-dn.net/?f=%5Cdfrac%7By%7D%7Bx%7D%3Dk)
Here, k=5.
![\dfrac{y}{x}=5](https://tex.z-dn.net/?f=%5Cdfrac%7By%7D%7Bx%7D%3D5)
![y=5x](https://tex.z-dn.net/?f=y%3D5x)
Hence the rate of change is constant that is 5.
Answer: plug in the top equation for what y equals into the bottom equation and then that should be a easy way to solve this
Step-by-step explanation: