Putting equation
0 = -16t² + 36t + 4
<span>0 = -8t² + 18t + 2 ← Complete the square to solve </span>
<span>-8(t² - 9t/2) = -2 </span>
<span>8(t² - 9t/4 + 81/64) = 2 + 81/8 </span>
<span>8(t - 9/8)² = 97/8 </span>
<span>(t - 9/8)² = 97/64 </span>
<span>t -</span><span> (t = 0) </span>
<span> (h = 0) at: </span>
<span>t = (9 + √97)/8 ≅ 2.356 seconds
hope it helps</span>
Answer:
I believe the answer is d, but im not quite sure
Step-by-step explanation:
Answer:
(x+1)(2x+5)
Step-by-step explanation:
f(x) = 2x² + 7x + 5
Factor the expression by grouping. First, the expression needs to be rewritten as 2x²+ax+bx+5. To find a and b, set up a system to be solved.
a+b=7
ab=2×5=10
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 10.
1,10
2,5
Calculate the sum for each pair.
1+10=11
2+5=7
The solution is the pair that gives sum 7.
a=2
b=5
2x²+7x+5 as (2x²+2x)+(5x+5).
(2x²+2x)+(5x+5)
Factor out 2x in the first and 5 in the second group.
2x(x+1)+5(x+1)
Factor out common term x+1 by using distributive property.
(x+1)(2x+5)
Answer:
The original number is 83
Step-by-step explanation:
let the number be ab
Sum of the two is 11
a + b = 11
tens digit a is one less than 3 times the ones digit
3b - a = 1
a = 3b - 1
3b -1 + b = 11
4b = 11 + 1
4b = 12
b = 12/4
b = 3
a = 3b - 1
a = 3(3) - 1
a = 9-1
a = 8
