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Sindrei [870]
3 years ago
8

11. Let f(x) = 2x² + 7x + 5

Mathematics
1 answer:
Lady_Fox [76]3 years ago
7 0

Answer:

(x+1)(2x+5)

Step-by-step explanation:

f(x) = 2x² + 7x + 5

Factor the expression by grouping. First, the expression needs to be rewritten as 2x²+ax+bx+5. To find a and b, set up a system to be solved.

a+b=7

ab=2×5=10

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 10.

1,10

2,5

Calculate the sum for each pair.

1+10=11

2+5=7

The solution is the pair that gives sum 7.

a=2

b=5

2x²+7x+5 as (2x²+2x)+(5x+5).

(2x²+2x)+(5x+5)

Factor out 2x in the first and 5 in the second group.

2x(x+1)+5(x+1)

Factor out common term x+1 by using distributive property.

(x+1)(2x+5)

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Mumz [18]
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    3x + 5(0) + 45 = 0
    3x = -45
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    x = -15

B. To find the x intercept, u must sub in 0 for y and solve for x

C. This is not true for a horizontal line because u can't sub in 0 for x because a horizontal line never crosses the x axis and therefore, does not have an x axis.

D. y int is -C/B....u find this by subbing in 0 for x and solving for y
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8 0
3 years ago
For my math it says someone ordered a poster with a height of 2 feet and width of 0.7 feet what is the area of the poster
Phantasy [73]
STEP-BY-STEP SOLUTION:

Let's solve this problem step-by-step.

As posters are generally rectangular in shape, we will establish the formula for the area of a rectangle which we will be using as displayed below:

Area = height × width

Now let's find the area of the postwr using the above formula.

Height = 2 feet

Width = 0.7 feet

Area = height × width

Area = 2 × 0.7

Area = 1.4 square feet

ANSWER:

Therefore, the answer is:

The area of the poster is 1.4 square feet.

Please mark as brainliest if you found this helpful! <3
Thank you : )
6 0
3 years ago
A) Two non-vertical lines have the same slope if and only if they are parallel.
kenny6666 [7]

Answer: D) If two parallel lines are cut by a transversal, then each pair of alternate interior angles is congruent.

Step-by-step explanation:

Since, By the Alternative interior angle theorem,

When two parallel lines are cut by the same transversal then the alternative interior angles made by the transversal on these parallel lines are congruent to each other.

Here AC ║ A'C'

⇒ AD ║ A'C'

⇒ parallel lines AD and A'C are cut by the same transversal A'D

⇒ ∠ CDB' ≅ ∠ BA'C' -------(1)

Similarly, When, AB ║ A'B

⇒ AB ║ A'D and AB ║EB'

⇒ Parallel lines AB and A'D are cut by the same transversal AD and Parallel lines AB and EB' are cu by the same transversal EB.

⇒ ∠ BAC ≅ ∠CDB' ------(2)   and  ∠ABC ≅ ∠BEB' -------(3)

Also, BC ║ B'C'

⇒ BE ║ B'C'

And, these paralle lines are cut by the same transversal B'E,

Thus, ∠BEB' ≅ ∠ A'B'C' ---------(4)

Thus, By equations (1) and (2),

∠ BAC ≅ ∠B'A'C ( By transitive property of equality )

And, By equation (3) and (4),

∠ABC ≅ ∠ A'B'C' ( By transitive property of equality )

5 0
3 years ago
Please help with this!!! 8 points!!!
Leviafan [203]

Answer:

d

Step-by-step explanation:

6 0
3 years ago
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