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Arturiano [62]
3 years ago
5

Which of the following linear functions has a graph which passes through points (−5,−2) and (−3,0)?

Mathematics
1 answer:
mylen [45]3 years ago
8 0
F(x)=x+3 hope that helps
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If f(x)=2x and g(x)= 1/x, what is the domain of (f*g) (x)
postnew [5]

Answer:

The domain of (f*g) (x) is the set of all real numbers; ( -∞, ∞)

Step-by-step explanation:

(f*g) (x) simply means we obtain the product of f(x) and g(x). We are given that;

f(x)=2x

g(x)= 1/x

(f*g) (x) = f(x) * g(x)

(f*g) (x) = 2x * 1/x = 2

This is a horizontal line defined everywhere on the real line. The domain of  (f*g) (x) is thus ( -∞, ∞)

7 0
3 years ago
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Which is equivalent to 64 1/4
professor190 [17]
It A i just took the quiz and got it but fail 

7 0
3 years ago
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5 squares are placed end to end as below (see pic). What is the perimeter of the rectangle formed by the squares?
Nataly_w [17]
2b: If x is 2.1, then one side of the rectangle is 2.1, and another is 2.1*5=10.5.  Thus, the perimeter is 2*(2.1+10.5)=2*12.6=25.2.

3: One side of the square with side-length three will not be on the outside, so we have 3*3=9 inches perimeter from the square of side-length 3.  The square of side-length 6 has 3 from the top side missing from the outer perimeter, because it coincides with a side of the square of side-length three.  This square contributes 6*4-3=33 inches.  The total perimeter is 33+9=42 inches.
5 0
3 years ago
For an angle Θ with the point (12, −5) on its terminating side, what is the value of cosine?
Pachacha [2.7K]
Given that the point (12,-5) which takes the form (x,y), This implies that:
opposite=-5
adjacent=12
thus using using Pythagorean theorem, the hypotenuse will be:
c^2=a^2+b^2
plugging the values we obtain:
c^2=(12)^2+(-5)^2
c^2=144+15
c^2=169
thus
c=13
but
cos θ=adjacent/ hypotenuse
therefore:
cos θ=12/13

Answer is option . D
5 0
3 years ago
1. Write a two-column proof for the following conjecture. You may not need to use all of the rows of the two-column table provid
marshall27 [118]

Answer:  

Given: ABCD is a parallelogram.

Prove: Angle A and B are supplementary and C and D are supplementary.

That is, m∠A + m∠B = 180° and m∠C + m∠D = 180°


                Statement                                                Reason

1. ABCD is a parallelogram              1. Given  

2.m∠A=m∠C and m∠B=m∠D         2. Definition of parallelogram.

3.m∠A+m∠B+m∠C+m∠D=360°      3. Definition of quadrilateral

4. m∠A+m∠B+m∠A+m∠B=360°     4. By substitution

⇒ 2( m∠A + m∠B ) = 360°

⇒ m∠A + m∠B = 180°

Similarly, m∠C + m∠D = 180°

5.∠A and ∠C are supplementary,  5. Def. of Supplementary

∠ B and ∠D are supplementary

7 0
3 years ago
Read 2 more answers
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