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Novay_Z [31]
4 years ago
13

At a playground, two young children are on identical swings. One child appears to be about twice as heavy as the other. Part A I

f you pull them back together the same distance and release them to start them swinging, what will you notice about the oscillations of the two children
Physics
1 answer:
neonofarm [45]4 years ago
3 0

Answer:

The motion of the lighter child would look faster than that of the heavier child, but both have the same period of oscillation.

Explanation:

Oscillation is a type of simple harmonic motion which involves the to and fro movement of an object. The oscillation takes place at a required time called the period of oscillation.

Since the swings are similar, the period of oscillation of the two children are the same and they would complete one oscillation in the same time. Though the oscillation of the lighter child seems faster than that of the heavy child, their masses does not affect the period of oscillation.

When a heavy object oscillates, its mass increases the drag or damping force, but not the period of oscillation. Thus, it oscillate slowly.

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Answer:

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Explanation:

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3 years ago
A satellite of mass 5460 kg orbits the Earth and has a period of 6520 s
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Answer:

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8 0
3 years ago
A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and v
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Opposite from the angle is 134.7905

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6 0
4 years ago
Read 2 more answers
1. 412.9 g of dry ice sublimes at room temperature. a. What’s changing? --- sublimation b. What constant will you use? ----- 25.
hoa [83]

1. 236 kJ

a. The phase (or state of matter) of the substance: from solid state to gas state (sublimation)

b. The enthalphy of sublimation, given by: \lambda=571 J/g

c. The equation to use will be Q=m\lambda, where m is the mass of dry ice and \lambda is the enthalpy of sublimation

d. The energy is being absorbed, because the heat is transferred from the environment to the dry ice: as a consequence, the bonds between the molecules of dry ice break and then move faster and faster, and so the substance turns from solid into gas directly.

e. The amount of energy being transferred is

Q=m\lambda=(412.9 g)(571 J/g)=2.36\cdot 10^5 J=236 kJ

2.  165 kJ

a. The phase (or state of matter) of the substance: from gas state to liquid state (condensation)

b. The latent heat of vaporisation of water, given by \lambda=2260 J/g

c. The equation to use will be Q=m\lambda, where m is the mass of steam that condenses and \lambda is the latent heat of vaporisation

d. The energy is being released, since the substance turns from a gas state (where molecules move faster) into liquid state (where molecules move slower), so the internal energy of the substance has decreased, therefore heat has been released

e. The amount of energy being transferred is

Q=m\lambda=(72.9 g)(2260 J/g)=1.65\cdot 10^5 J=165 kJ

3. 3.64 kJ

a. Only the temperature of the substance (which is increasing)

b. The specific heat capacity of silver, which is C_s = 0.240 J/gC

c. The equation to use will be Q=m C_s \Delta T, where m is the mass of silver, Cs is the specific heat capacity and \Delta T the increase in temperature

d. The energy is being absorbed by the silver, since its temperature increases, this means that its molecules move faster so energy should be provided to the silver by the surroundings

e. The amount of energy being transferred is

Q=m C_s \Delta T=(39.2 g)(0.240 J/gC)(412.9^{\circ}C-25.9^{\circ}C)=3641=3.64 kJ

4. 89 kJ

a. Both the phase of the substance (from solid to liquid) and then the temperature

b. The latent heat of fusion of ice: \lambda=334 J/g and the specific heat capacity of water: C_s=4.186 J/gC

c. The equation to use will be Q=m\lambda + m C_s \Delta T, where m is the mass of ice, \lambda the latent heat of fusion of ice, Cs is the specific heat capacity of water and \Delta T the increase in temperature

d. The energy is being absorbed by the ice, at first to break the bonds between the molecules of ice and to cause the melting of ice, and then to increase the temperature of the water

e. The amount of energy being transferred is

Q=m\lambda +m C_s \Delta T=(156.3 g)(334 J/g)+(156.3 g)(4.186 J/gC)(56.232^{\circ}C-0^{\circ}C)=8.9\cdot 10^4 J=89 kJ

6 0
3 years ago
A physics student spins a bucket of water over her head in a circular path in order to demonstrate centripetal force. She fills
Ronch [10]

Answer:

The first case requires more force to spin de bucket.

Explanation:

As we know, the centripetal force is directly proportional to the mass, the equation is given by:

F_{c}=ma_{c}

The first case has a quarter more water than the second case, therefore the first case requires more force to spin de bucket.

I hope it helps you!

3 0
3 years ago
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