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chubhunter [2.5K]
3 years ago
7

Derive formula for pressure in any liquid

Physics
1 answer:
mestny [16]3 years ago
7 0

Answer:

Besides, we often calculate pressure for gases and fluids. In those conditions, the pressure of liquid or gas is equal to the density of that fluid multiplied by the acceleration due to the gravity and the height (depth) of the fluid above a certain point. Pressure = density of fluid × acceleration due to gravity × height of the fluid column

Explanation:

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Answer:

green pigment

Explanation:

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Alla [95]

Explanation:

The acceleration of a body is defined as the rate of change of velocity per unit time. Its mathematical form is given by :

a=\dfrac{v-u}{t}

Here,

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v is final speed

t is time taken

Uniform acceleration means that the velocity of an object changes by an equal amount in every equal time period. Hence, the correct option is (c) " Its velocity increases by increasing amounts in equal time intervals".

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It takes 0.5 s to complete a 3 m wave. What is the speed of the wave?
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im not a point taker i help when people need help  

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4 0
3 years ago
A skier starts at the top of a very large, frictionless snowball, with a very small initial speed, and skis straight down the si
dangina [55]

Answer:

The answer to the question is

At the instant she loses contact with the snowball, the angle (alpha) a radial line from the center of the snowball to the skier make with the vertical is 48.2 °

Explanation:

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m·g·cos θ - N = m\frac{v^2}{R}

Where  N = 0 at the point the skier leaves the snowball

That is

 m·g·cos θ  = m\frac{v^2}{R}

The height from which the skier drops from the snowball is given by

h = r - r·cosθ

Therefore the potential energy of the skier just before leaveing the snowball is

m·g·h = m·g·r·(1-cosθ)

From conservation of energy, the total energy of the skier is constant which means that is the potential energy is transformed to kinetic energy of the form

PE = KE That is  

\frac{1}{2} mv^2 = m·g·r·(1-cosθ) or

m\frac{v^2}{R} = 2·m·g·(1-cosθ) Howerver since   m·g·cos θ  = m\frac{v^2}{R} then we have

m·g·cos θ  = 2·m·g·(1-cosθ)  which gives

cosθ = 2·(1-cosθ) or 3·cosθ = 2

or cosθ =  \frac{2}{3} and θ = cos^{-1}\frac{2}{3} = 48.1896851 °

≈48.2 °

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4 years ago
A mechanoreceptor in the papillary layer of the dermis that responds to fine touch is a
yan [13]
Answer: tactile (Meissener) corpuscle.

Hope this helps.
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