Answer:
b
Explanation:
because if you freeze somthing you do not gain heat you loss heat.
Answer:
Lighter
Explanation:
In practice, the lamp is powered by an AC voltage source which is connected in series with an inductive ballast in order to supply an approximately constant current to the lamp, rather than a constant voltage. This helps to provide a stable operation. The ballast is usually inductive rather than simply being resistive to maximize resistive losses.
As this lamp current tending to zero-current point and shadow cast by the sodium flame becoming lighter.
Answer:
1 m = 39.37 in = 39.37/12 ft = 3.28 ft
V = 1145 k/hr = 1145k/hr * 6076 ft/k = 6957020 ft / hr
V = 6957020 ft/hr / 3600 s/hr = 1933 ft/sec
V = 1933 ft/sec / (3.28 ft / m) = 589 m/s
Check:
88 ft/sec = 60 mph
(1145 k/hr * 6076 ft / k) 3600 sec/hr = 1933 ft/sec = 589 m/s
1933 ft/sec / (88 ft/sec) * 60 mph = 1318 mph
Also, 1318 / 1145 = 6076 / 5280 as it should
The second world war, and its war weapons, such as the v-2 rockets, had a great impact on the world until today, to answer this question we need that...
<h3>
V-2 factory </h3>
On April 11, 1945, US troops took the town of Bleicherode, in the Kohnstein region, where the V-2 factory was located. From there about 100 complete V-2s and thousands of parts and equipment were "captured" as war loot and transferred to the United States, where they formed the basis for practical studies of the missile defense program.
With this information, we can say that because it was a base discovered by US troops, none of the alternatives is correct, as it was not the Soviets who discovered it, and that the base was also located in the central part of Germany.
<u>The </u><u>v-2 factory</u><u> was located in </u><u>Kohnstein, central germany,</u><u> by this claim, </u><u>none of the alternatives is correct.</u>
Learn more about second world war brainly.com/question/7013432
Answer: 15 cm
Explanation:
According to the Lens Equation we have the following:
(1)
Where:
is the focal length
is the distance between the candle (the object) and the lens
is the distance between the image and the lens
Isolating :
(2)
Solving:
(3)
Finally:
This is where the image is located
