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Nastasia [14]
3 years ago
14

5 x 2 + 3into power 2

Mathematics
1 answer:
galina1969 [7]3 years ago
5 0
The answer should be 19 if you mean 3 to the power of 2. as listed below.

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15 = r -6 what does r equal
77julia77 [94]

Answer:

21-6=15

Step-by-step explanation:

3 0
2 years ago
the number of men is five eights of the number of women working in a factory if there is 24 more women than men how many workers
Anna [14]

Answer:

104

Step-by-step explanation:

women = 8/8

men = 5/8

all workers = 8/8 + 5/8 = 13/8

extra women workers = 8/8 - 5/8 = 3/8

so...

3/8 = 24

13/8 = x

( cross multiplication method)

3/8 x = 39

x = 104

Hence, there are 104 workers

6 0
1 year ago
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Pls help me <br> plsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss
Svet_ta [14]

Answer:

x ≤ 2

Step-by-step explanation:

3 0
2 years ago
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BRAINLIEST TO CORRECT QUICK
frutty [35]
The answer will be (3/4)>-7 1/2
3 0
2 years ago
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For parts a and bâ, use technology to estimate the following. âa) The critical value of t for a 90â% confidence interval with df
rjkz [21]

Answer:

a) For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

b) For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

Part a

For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

Part b

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

3 0
3 years ago
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