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KATRIN_1 [288]
3 years ago
8

Solve for x +6 = 12 I'm gonna mark this as brainy

Mathematics
1 answer:
Vesna [10]3 years ago
6 0

Answer:

x=6

Step-by-step explanation:

To solve this problem,

firstly make x to stand alone

subtract 6 from both sides of the equation

x+6-6=12-6

x= 6

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PLEASE HELP ASAPPP!!!!
Mashutka [201]

Answer:

\sqrt{(\frac{9c^{16} }{d^{4} })^{3}   }=\frac{9c^{16} }{d^{4} } \sqrt{\frac{9c^{16}}{d^{4}} } \\\\=  \frac{9c^{16} }{d^{4} }.\frac{3c^{8} }{d^{2} }=\frac{27c^{24} }{d^{6} }

=> Amelia's answer is incorrect

Step-by-step explanation:

8 0
3 years ago
HELPPPP FIND THE AREA
GuDViN [60]

you can just split the figure in 2 separate figures and them add the areas:

area rec. 1:

3m×3m= 9m²

area rec. 2:

3m× (2m+3m)

= 3m×5m

=15m²

total area:

9m²+15m²= 24m²

5 0
2 years ago
Read 2 more answers
Help pleaseeee pleaseeee pleaseeee
Murljashka [212]
We have the same workbook lol
The answer is
Drums: 2/4
milks 4/9
(unless your teacher wants it improper.)
4 0
3 years ago
Find an equation for the line below.
vodka [1.7K]

Answer:

A(-6,-5) B(4,1)

Step-by-step explanation:

am not that sure

7 0
2 years ago
Read 2 more answers
A. The lengths of pregnancies in a small rural village are normally distributed with a mean of 266 days and a standard deviation
Darya [45]

Step-by-step explanation:

a.

mean = 266

sd = 14

cumulative probability = 0.01 so the standard score = -2.33 and 2.33 to the right and left

we find X-upper and X-lower

X-lower = 266-2.33*14 = 233.38

X-upper = 266+2.33*14 = 298.62

Between 233.38 and 298.62

we have sample size = 35

X-lower = 266-2.33*14/√35 = 260.49

X-upper = 266+2.33*14/√35 = 271.5

Between 260.49 and 271.5

b. cumulative probaility = 0.25

standard score = 1.96 to the right and left

x-lower = 6.9-1.96x0.9 = 5.14

x-upper = 6.9+1.96x0.9 = 8.66

Between 5.14 and 8.66

if sample size = 45

x-lower = 6.9-1.96*0.9/√45 = 6.64

x-upper = 6.9+1.96*0.9/√45 = 7.2

Between 6.64 and 7.2

c. standard scores would have cut off value at 0.67 and -0,67

x-lower = 265.3-0.67x15.2 = 255.12

x-upper = 265.3+0.67x15.2 = 275.48

Between 255.12 and 275.48

d. we will have critical values at 1.00 and -1.00

X-lower = 265-1x16 = 249

x-upper = 265+1x16 = 281

Between 249 and 281

with sample size = 44

x-lower = 265-1x16/√44 = 262.59

x-upper = 265+1x16/√44 = 267.41

Between 262.59 and 267.41

3 0
3 years ago
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