Answer: increased burning of fuels
Explanation:
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Answer: Germline mutation
A germline mutation is a mutation in the fully developed germ cells (sperm and ovum). These defective mutated cells fuse to form zygote. The zygote rapidly produces all somatic and germline cells in the offsprings which are also mutated. Therefore, mutation is transmitted from parents to offsprings. Cystic fibrosis is a result of germline mutation. This disease is hereditary in nature passes from parents to the offsprings. If a child receives CFTR (cystic fibrosis transmembrane conductance regulator) mutated gene from both the parents than the child will be affected by the symptoms of this disease. If the child receives a single copy of CFTR gene from either of the parent than the child will be the carrier of disease.The mutated gene may be present in the germline cells of the parent or on all the body cells.
When a BB male and a Bb female are crossed, 50% BB and 50% Bb genotypes are produced and a 100% black phenotype.
The entire number of genes that an organism receives from its parents makes up its genotype. Alleles, which are pairs of these genes, are found. One gene is dominant and one gene is recessive in each allele.
The dominant gene is always expressed in a cross if it is present. Only when a pair of alleles is made up of two recessive genes does the recessive gene express itself. In this instance, the white fur is subordinate to the black fur. White fur is represented as b, while black fur is represented as B.
We can see that when we cross the BB male and Bb female, we will get a genotype that is 50% BB and 50% Bb, as well as a phenotype that is 100% black fur.
Parents: BB x Bb
Gametes: B, B, and B, b
Offspring: BB, BB, Bb, Bb
The genotypic ratio = 1:1
The phenotypic ratio = 1:0
Genotype probabilities:
P(BB) = 2/4 = 0.5 or 50%
P(Bb) = 2/4 = 0.5 or 50%
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