Answer:
Your answer is 3.1
Step-by-step explanation:
Wherever you see j, substitute 5. Wherever you see k, substitute 3
1. Set up: 
2. Multiply 4.7 * 5, to get 23.5
3. Multiply 6.8 * 3 to get 20.4
4. Subtract 23.5-20.4
5. Final anwer - 3.1
Hope this helps!
Answer:
I'll give you a hint
Step-by-step explanation:
The angles are not supplementary, which means they add up to 180 degrees, they are complementary, which means they add up to 90 degrees
Hope this helps!
The two containers hold 328 ounces at the they hold same amount of water.
<u>Step-by-step explanation:</u>
The equations below model the ounces of water, y, in each container after x minutes.


At the time after the start when the containers hold the same amount of water, the two equations must be equal.
⇒
The first step is to divide everything by 2 to make it simplified.
⇒ 
Now put everything on the left
.

Add the like terms together to further reduce the equation

Factorizing the equation to find the roots of the equation.
Here, b = -12 and c = -28
where,
- b is the sum of the roots ⇒ -14 + 2 = -12
- c is the product of the roots ⇒ -14 × 2 = -28
- Therefore, (x-14) (x+2) = 0
- The solution is x = -2 or x = 14
Take x = 14 and substitute in any of the given two equations,
⇒ 
⇒ 
⇒ 328 ounces
∴ The two containers hold 328 ounces at the they hold same amount of water.
Answer:
1. x = 39.67
2. x = 15
3. x = 49.29
4. x = -12.8
5. x = 96
6. x = 42
7. x = 36
8. x = 0
9. x = 78
Step-by-step explanation:
Just remember to always isolate the unknown. Here are the solutions to your problem. I will explain each step for the first for you to give you an idea how the others were worked out.
1.
Add 2 to both sides to get rid of -2 on the left side.

Multiply both sides by 7 to get rid of 7 on the left side.

Divide both sides by 3 to get rid of 3 on the left side.

You could also transpose everything by the x to the other side of the equation. Just remember that whatever OPERATION used on the original side, must be opposite on the other side. I'll use the second problem to show this.

Transpose 1 on the left to the right. It is addition on the left, then it would be subtraction on the other side.

Transpose 5 from the left side to the right. It is division on the left, then it would be multiplication on the right.

Transpose 2 from the left side to the right. It is multiplication on the left, then it would be division on the right.

Let's move on with the rest now.
3.

4.

5.

6.

7.

8.

9.
