Answer:
Since
x
is on the right side of the equation, switch the sides so it is on the left side of the equation.
x
2
−
2
x
+
3
=
G
(
x
)
Multiply
G
by
x
.
x
2
−
2
x
+
3
=
G
x
Subtract
G
x
from both sides of the equation.
x
2
−
2
x
+
3
−
G
x
=
0
Use the quadratic formula to find the solutions.
−
b
±
√
b
2
−
4
(
a
c
)
2
a
Substitute the values
a
=
1
,
b
=
−
2
−
G
, and
c
=
3
into the quadratic formula and solve for
x
.
−
(
−
2
−
G
)
±
√
(
−
2
−
G
)
2
−
4
⋅
(
1
⋅
3
)
2
⋅
1
Simplify.
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x
=
2
+
G
±
√
G
2
+
4
G
−
8
2
The final answer is the combination of both solutions.
x
=
2
+
G
+
√
G
2
+
4
G
−
8
2
x
=
2
+
G
−
√
G
2
+
4
G
−
8
2
Step-by-step explanation:
Answer:
is this correct. I hope it is
- Subtraction can be thought of as the inverse operation of addition, OR as addition itself, if you look at it as adding a negative number.
- The number line allows us to interpret subtraction (or addition of a negative) geometrically; we can view it as a movement to the left on the number line with a distance equal to the number being subtracted.
- Lastly, the value of any expression a - b (where a and b are real numbers) is determined by the relative sizes of the numbers. If a > b, then a - b > 0 (a positive result). If b > a, then a - b < 0 (a negative result.
Answer:
3 3/4 yards
Step-by-step explanation:
The area of a rectangle can be found by multiplying length * width. Since we have the area of the patio and the length, all we need to do to find the width is divide 5 5/8 (area) / 1 1/2 (length) =3 3/4 yards (width).
To check if this is correct, we can solve 1 1/2 * 3 3/4 = 5 5/8 yards.
Hope this helps!
Answer:
Step-by-step explanation:
- Use of low <em>of sines</em>
- <em>Consider triangle CEN</em>
- <em>Bearing of angle counted from zero to the vector of flight</em>
<u>We have </u>
- ∠CNE = complementary with 44° ⇒ m∠CNE = 90° - 44° = 46°
- NE = b = 545 km
- EC = a = 680 km
- ∠ECN = x
<u>Find the measure of angle x:</u>
- sin 46° / a = sin x / b
- sin 46° / 680 = sin x / 545
- sin x = 545 sin 46 deg / 680
- x = arcsin (545 sin 46 deg / 680)
- x = 35° (rounded)
<u>Bearing of the flight from Elgin to Canton is:</u>
- 270° - 35° = 235° as the vector is in the third quadrant