When two parallel lines are intersected by a transversal, the same-side exterior angles are supplementary. That means that their sum is 180.
Using that logic, if the two roads were parallel, then the sum of their same-side exterior angles will add up to 180. Yet their same-side exterior angles add up to 170 (130 + 40 = 170), hence they can't be parallel.
See the drawing attached below.
Using supplmenatry angles (two angles whose sum of measures add up to 180 or a straight line), we can say that:
m<DIE + m<HID = 18
40 + m<HID = 180
m<HID = 140
Similarly:
m<BHC + m<CHI = 180
130 + m<CHI = 180
m<CHI = 50
Using verticle angles therome, (when two lines intersect, the angles opposite to eachother are congruent, or have the same measure), we can say that:
m<DIE = m<GIH = 40
m<GIE = m<HID = 140
m<CHI = m<AHB = 50
m<BHC = m<AHI = 130
To find the average, combine all the numbers together and divide by the amount there is.
-7 + 2 - 9 - 4 - 7 = -25
-25/5 = -5
-5 is your average temperature
hope this helps
Answer:
y = 11(x -1) +6
Step-by-step explanation:
The slope at the given point is ...
y' = 14x -3x^2 = 14(1) -3(1^2) = 11
Then the point-slope equation for the line can be written as ...
y = m(x -h) +k . . . . . . for slope m at point (h, k)
y = 11(x -1) +6
Do 2*3 then do the answer divided by 18 to get the answrr