If angle AEC is 90° and angle AEB bisects it and is 45° that right there proves that angle AEB bisects angle AEC
X= r-h/y
h= xy-r/-1
r= xy+h
Answer:
98
Step-by-step explanation:
f(x) = 10x² + 8
= 10(-3)² + 8
= 10 (9) + 8
= 90 + 8
= 98
first get all variables on the same side, then use elimination to solve.
x = -3
y = -11
