The trapezoid ABCD has bases AB = 15 and CD = 5, thigh AD = 9 and diagonal BD = 12. Find:
1 answer:
Answer:
The height of the trapezoid is 6.63 units
The perimeter of the trapezoid is 38 units
Step-by-step explanation:
Whenever a geometry problem is given, it is often useful if it is sketched out. A sketch of this problem can be found in the image attached.
A)
We can see that a right-angled triangle is formed between points BED, with line BE being the height, h.
To get the dimensions of the line EB, we subtract the dimensions of DC from AB. This will give 15 -5 = 10
hence the dimensions of the righ angled triangle are
DE= h
DB = 12 (diagonal)
EB = 10
From Pythagoras' theorem,
The height of the trapezoid is 6.63
B)
We can get the perimeter of the trapezoid by adding the dimensions of all four sides together.
This will be
AD + DC + CB + AB
However we can assume for this case that it is a symmetrical trapezoid, and hence AD = CB
Thus, perimeter =
2 (AD) + DC +AB
2(9) +5 +15 = 38.
The perimeter of the trapezoid is 38 units
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Answer:
1.5 in
Step-by-step explanation:
Let x be the width of the frame.
Side of print=10 in
Area of frame=69 square in
We have to find the width of the frame.
Side of frame=10+x+x=10+2x
Area of square=
By using the formula
Area of print=
Area of frame with print=
Area of frame=Area of frame with print-Area of print
Because Side is always positive.
Hence, width of frame=1.5 in
