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sukhopar [10]
3 years ago
7

Help me on this Because I don’t get it

Mathematics
2 answers:
Furkat [3]3 years ago
6 0
I’m 100000% it’s true
4/9x +2=5/6
8x +36=15
8x=15-36
8x=-21
x= -21/8
x= -2 5/8

Hope this helps!
Lady_Fox [76]3 years ago
5 0

9514 1404 393

Answer:

  8x +36 = 15

Step-by-step explanation:

The fractions can be made to disappear by multiplying the equation by their least common denominator. That number is 18.

  18(4/9x +2) = 18(5/6)

  8x +36 = 15

__

The solution is x = -21/8.

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Scientists are studying the frog population in a pond. The function g(x)=14(1.75)x can be used to determine the number of frogs
dimulka [17.4K]

Answer:

A. 0.4

Step-by-step explanation:

4 0
3 years ago
---- PLEASE HELP <3 .. with steps :( <3
Zielflug [23.3K]

1) 6, 18, 54

2) 5/3, 14/9, 41/27

3) 1.5, 2.5, 2.5

Step-by-step explanation:

1)

The function that we have in this problem is

g(x)=3x

We want to find the first 3 iterations.

The initial value is:

x = 2

To find the value of the 1st iteration, we just substitute this value into the expression of the function, and we get:

g_1(x)=3x=3\cdot 2 = 6

The to find the value of the 2nd iteration, we just substitute this value into the expression of the function, and we get:

g_2(x)=3\cdot g_1(x)=3\cdot 6 = 18

Finally, the 3rd iteraction is given by:

g_3(x)=3g_2(x)=3\cdot 18=54

2)

Here in this problem the function that we have to use is

g(x)=\frac{1}{3}x+1

The initial value is

x=2

So the first iteration is given by

g_1(x)=\frac{1}{3}\cdot 2 + 1 = \frac{5}{3}

To find the 2nd iteration, we substitute this value into g(x) again:

g_2(x)=\frac{1}{3}g_1+1=\frac{1}{3}\cdot \frac{5}{3}+1=\frac{5}{9}+1=\frac{14}{9}

Finally, to find the 3rd iteration, we substitute this value into g(x) again:

g_3(x)=\frac{1}{3}\cdot \frac{14}{9}+1=\frac{14}{27}+1=\frac{41}{27}

3)

The function in this problem is

g(x)=-|x-2|+3

The initial value is

x = 0.5

So, the first iteration is:

g_1(x)=-1|0.5-2|+3=-1|-1.5|+3=-1\cdot 1.5 +3=-1.5+3=1.5

The second iteration is given by

g_2(x)=-|g_1-2|+3=-|1.5-2|+3=--0.5+3=2.5

Finally, the 3rd iteration is

g_3(x)=-|g_2-2|+3=-|2.5-2|+3=-0.5+3=2.5

5 0
3 years ago
I need to.find out what the blanks are please comment
Anni [7]
First blank: 8
Second blank: 5
Third blank: 20
Fourth blank: 60

6 0
3 years ago
A volleyball reaches its maximum height of 13 feet, 3 seconds after its served. Which of the following quadratics could model th
julsineya [31]
Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.

We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.

8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%2081" id="TexFormula1" title=" {x}^{2} + 81" alt=" {x}^{2} + 8
borishaifa [10]
X to the power of two+81
5 0
3 years ago
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