Because all numbers that are divisible by 10 is divisible by 5, all numbers that are divisible by 8 is divisible by 2 and 4, all numbers divisible by 6 is divisible by 2 and 3, we only need to find the smallest common multiple of 6,7,8,9,10 and 11
find the prime factors of each:
2,3
7
2,2,2,
3,3,
2,5,
11
factors that are shared can be used only once, so we have:
2*7*3*11*3*2*5*2=27720
19/57 is the greatest fraction out of them.
8.45 rounded to the nearest tenth is:
8.6 because 5 is equal to 5
Hope I Helped You!!! :-)
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The line is stretched from M to P
The point O is in between M and P, so the length OM add length OP will give the full length of MP
OM =

OP =

The length MP = OM + OP =

If N is the midpoint of MP, then the length MN is half of the length MP
MN =