Formula for midpoint between two points is M(x,y)
x=(x1+x2)/2 and y=(y1+y2)/2
In our case (x1,y1)=(m,b) and (x2,y2)=(0,0)
x=(m+0)/2=m/2 and y=(b+0)/2=b/2 M(m/2,b/2)
Good luck!!!
Answer:
x=5
Step-by-step explanation:
Answer:
- g(2.95) ≈ -1.8; g(3.05) ≈ -0.2
- A) tangents are increasing in slope, so the tangent is below the curve, and estimates are too small.
Step-by-step explanation:
(a) The linear approximation of g(x) at x=b will be ...
g(x) ≈ g'(b)(x -b) +g(b)
Using the given relations, this is ...
g'(3) = 3² +7 = 16
g(x) ≈ 16(x -3) -1
Then the points of interest are ...
g(2.95) ≈ 16(2.95 -3) -1 = -1.8
g(3.05) ≈ 16(3.05 -3) -1 = -0.2
__
(b) At x=3, the slope of the curve is increasing, so the tangent lies below the curve. The estimates are too small. (Matches description A.)
You don't have the question out for me to answer so could you add the question to this like a picture or something?