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Marina86 [1]
3 years ago
10

Analyze the table, which shows the number of 6th graders from two classes who play handheld games. PLS WILL GIVE BRAILYIEST

Mathematics
1 answer:
Mazyrski [523]3 years ago
4 0

Answer:

FALSE

Step-by-step explanation:

Proportional would mean that the ratios of "play handheld games" to "total students" for each 6th grade class would be equal. Let's check:

Mrs. McKenna

28/32 = 7/8

and

Rodriguez

26/30 = 13/15

Certainly, 7/8 and 13/15 are NOT proportional [they aren't same when reduced]

Thus, the answer is FALSE

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Jason’s salary and Karen’s salary were each p percent greater in 1998 than in 1995. What is the value of p ? (1) In 1995 Karen’s
shtirl [24]

Answer: Hi, first lets give our variables some names.

Lets call Ks to Karen's salary and Js to Jason's salary.

then, in 1995:

Ks₁ - Js₁ = 2000$

in 1998:

Ks₂ - Js₂ = 2440$

now, we know that  Ks₂ = (1 +p)*Ks₁ and   Js₂ = (1+p)*Js₁

so we can write the second equation as:

p*(Ks₁ - Js₁ ) = 2440$

replacing the parentesis with the first equiation

(1+p)*(2000$) = 2440$

(1+p)= 2440/2000 = 1.22

so p = 0.22, or a 22%

8 0
3 years ago
Rita and Tina each make $11 an hour working as cashiers at a supermarket. Last week, Rita worked r hours while Tina worked t hou
Alexxx [7]

Answer:

11(t+r)+35

Step-by-step explanation:

they make 11 dollars an hour so you have to multiply 11 by t hour an r hours. then only one of them worked overtime so you add 35.

5 0
3 years ago
Anyone know what the answer is ?
alina1380 [7]
A perpendicular bisector
this means the length IJ=JK and the angles IJB, BJK are 90° (and their congruent angles too)

but this does not mean AB=IK, because their lengths can be arbitrary
for a similar reason AJ=IJ is wrong, essentially the same statement but with half lengths
BI=BK is true, because it is a bisector of IK this means the sides IJ=JK and JB is a shared side, therefore also having the same length. We also know IJB and BJK are congruent angles, so all in all these are congruent triangle and therefore also share the side length
BI=AK is false, because we don't know where the intersection point j is on AB, it could split the length into any arbitrary ratio, in case these are two equal sides then it would be true, but it doesn't hold for all other possibilities

so BI=BK is the solution
3 0
3 years ago
How to find missing angle to right triangle
weqwewe [10]
Can you post a picture of the question?
8 0
3 years ago
Write the vector v in the form aiplusbj​, given its magnitude left norm Bold v right norm and the angle alpha it makes with the
photoshop1234 [79]

Answer:

6\sqrt{3}i-6j

Step-by-step explanation:

Given:

The magnitude, v=12

The angle \alpha it makes with the positive​ x-axis =150^0

Now for a vector (x,y)

  • \alpha =tan^{-1}(\frac{y}{x} ) ; and
  • v=\sqrt{x^2+y^2}

Therefore:

150 =tan^{-1}(\frac{y}{x} )\\\frac{y}{x} =tan 150\\\frac{y}{x}=-\frac{\sqrt{3} }{3}

y=-\frac{x \sqrt{3}}{3}

Similarly:

v=\sqrt{x^2+y^2}\\12=\sqrt{x^2+y^2}\\12^2=x^2+y^2\\144=x^2+y^2

144=x^2+(-\frac{x \sqrt{3}}{3} )^2\\144=x^2+\frac{3x^2}{9} \\144=\frac{4x^2}{3}\\4x^2=144 X 3=432\\x^2=108\\x=6\sqrt{3}

Recall that:

y=-\frac{x \sqrt{3}}{3}\\y=-\frac{6\sqrt{3}  \sqrt{3}}{3}=-6

Therefore: (x,y)=(6\sqrt{3}, -6)

The vector in the form ai+bj is therefore:

6\sqrt{3}i-6j

6 0
3 years ago
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